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xxMikexx [17]
3 years ago
6

PLEASE HELP WITH GIVE LIKE IF I DONT HAVE BRAINLIEST

Physics
1 answer:
just olya [345]3 years ago
3 0

All of these could apply except changing. Any object at rest or in constant motion has balanced forces acting upon it.

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which of the seasons is celebrated by many northern cultures with festivals, often symbolizing rebirth?
tensa zangetsu [6.8K]
I’m not entirely certain, but usually, spring symbolizes rebirth.
4 0
3 years ago
Read 2 more answers
How to measure the speed of sound in air?
Leona [35]

STEP ONE:


Let  you and your friend stand as far away as possible from a large reflecting wall and clap your hands rapidly at a regular rate.  


STEP TWO:


Adjust this rate until each clap just coincides with the return of an echo of its predecessor, or until clap and echo are heard as equally spaced.


STEP THREE:


Use a stopwatch to find the time between claps, t. Make a rough measurement of distance to the wall, s. Thus the speed of sound, v = 2s/t

8 0
3 years ago
Physics help, thank you guys so much!
katrin2010 [14]

Answer:

 Δt = 5.85 s

Explanation:

For this exercise let's use Faraday's Law

           emf = -  \frac{d \phi}{dt} -  d fi / dt

           \phi = B. A

           \phi = B A cos θ

The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.

suppose a linear change of the magnetic field

            emf = - A \frac{B_f - B_o}{ \Delta t}

             Dt = - A  \frac{B_f - B_o}{emf}

the final field before a fault is zero

       

let's calculate

            Δt = - 0.046 (0- 1.4) / 0.011

            Δt = 5.85 s

4 0
3 years ago
EASY BRAINLIEST PLEASE HELP!!
Soloha48 [4]

Answer:

Solution given:

frequency[f]=x

velocity[V]=15000m/s

wave length=59m

we have

wave length=\frac{V}{f}

59m=\frac{15000}{x}

x=\frac{15000}{59}=254.Hz

frequency=254Hz

7 0
2 years ago
Read 2 more answers
Constants A capacitor is connected across an ac source that has voltage amplitude 59 0 V and frequency 77 0 Hz Part C What is th
Vladimir79 [104]

Answer:

C = 1.77 \times 10^{-4} F

Explanation:

As we know that in AC circuit we have

V = i x_c

here we have

V = 59 V

i = 5.05 A

so we will have

x_c = \frac{59}{5.05}

x_c = 11.68 ohm

also we know that

x_c = \frac{1}{\omega C}

here we will have

11.68 = \frac{1}{(2\pi 77)C}

C = 1.77 \times 10^{-4} F

7 0
2 years ago
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