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Harlamova29_29 [7]
3 years ago
8

3. When you graph the motion of an object, you put ____ on the horizontal axis and ____ on the axis.   a.  speed, time   b.  dis

tance, time   c.  time, speed   d.  time, distance
Physics
2 answers:
Papessa [141]3 years ago
7 0
The answer is B. distance , Time
Mrac [35]3 years ago
5 0
(c) and (d) can both be correct. It just depends on whether you're graphing speed or distance.
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1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic​
Korvikt [17]

51.448 g is the required answer!

8 0
3 years ago
A 55.6 kg ice skater is moving at 1.73 m/s when she grabs the loose end of a rope, the opposite end of which is tied to a pole.
GarryVolchara [31]

Answer:

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

Explanation:

Step 1: Data given

Mass of the ice skater = 55.6 kg

Velocity = 1.73 m/s

She then moves in a circle of radius 0.608 m around the pole.

Step 2:

Force exterted by the horizontal rope is the centripetal force acting on theice skater:

Fc = M*ac

⇒ with ac = v²/r

Fc = M * v²/r

Fc = 55.6 * 1.73²/0.608

Fc =273.69 N

The force exerted by the rope on her arms is 273.7 N = 0.274 kN

7 0
3 years ago
In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between
kap26 [50]

The separation between the slits is d = 8.96

What is fringe width?

  • Fringe width is the distance between two consecutive bright spots (maximas, where constructive interference take place)
  • Or two consecutive dark spots (minimas, where destructive interference take place).

Fringe width is given by β = λL/d

In the first case fringe width is β1 = λLA /d   = 625 x 10-9 x 0.36 / ( 1.4 x 10-5 )  = 0.016071428 m

The total width of the screen is 0.2 m . So, on one side of the central maximum, the width is 0.1 m

No. of fringes in this 0.1m = 0.1 / 0.016071428  = 6.222  

So, since there is a bright fringe after every fringe width, the number of bright fringes on one side of central maximum is 6.

In the second case fringe width is β1 = λLAB /d   = 625 x 10-9 x 0.25 / ( 1.4 x 10-5 )  = 0.011160714 m

The total width of the screen is 0.2 m . So, on one side of the central maximum, the width is 0.1 m

No. of fringes in this 0.1m = 0.1 / 0.011160714  = 8.96

So, since there is a bright fringe after every fringe width, the number of bright fringes on one side of central maximum is 8.  The ninth one will not be seen since the screen is less a little less in width.

Learn more about fringe width

brainly.com/question/14438105

#SPJ4

<u>The complete question is -</u>

In a setup like that in Figure 27.7, a wavelength of 625 nm is used in a Young's double-slit experiment. The separation between the slits is d = 1.4 × 10-3 m. The total width of the screen is 0.20 m. In one version of the setup, the separation between the double slit and the screen is LA = 0.36 m, whereas in another version it is LB = 0.25 m. On one side of the central bright fringe, how many bright fringes lie on the screen in the two versions of the setup? Do not include the central bright fringe in your counting. --Tm = 3 (Bright fringe) ++m = 0 (Bright fringe) -m = 3 (Bright fringe) Figure 27.7

5 0
1 year ago
Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja
igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

<u>a = 3.33 m/s²</u>

8 0
3 years ago
If you change the number of loops in a solenoid, what happens to the strength of the magnetic field of an electromagnet?
zhenek [66]

The strength of the magnetic field is proportional to the number of turns in the solenoid; this means that the strength of the field will increase or decrease as you increase or decrease the number of turns in the coil, respectively - they are directly related.

Hope this helps!

6 0
3 years ago
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