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nexus9112 [7]
2 years ago
9

If an object has a mass of 15 kg and has a weight of 30 N, on some remote

Physics
1 answer:
deff fn [24]2 years ago
6 0
If a object has a mass of 15kg and has a weight of 30N, on ... 0.96kg
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Which best describes the law of conservation of mass? The coefficients in front of the chemicals in the reactants should be base
likoan [24]

Answer:

Explanation:

1. when both sides of the reactants and the products are equal

like h+oh ⇒ h20

hydrogen has 2 atoms on both sides and oxygen  has one  on both sides

2. no they are put to balance the equation

3. nope they are treated equally as all the other states

4. no if u are talking about a formula unit like NaCl for example it is aqueous not each element taken on its own if u are talking about just elements then i said before all states are treated equally

5. yup

6 0
3 years ago
A toy remote control car drives in a circle (the controller is stuck). It makes 8 revolutions in 14
IceJOKER [234]

Answer:

Period for 1 revolution is 1.75 seconds

Explanation:

given data

revolutions R = 8

time t = 14 seconds

to find out

What is the period

solution

we know that Period is the time per revolution

so here period formula that is express as

period = \frac{R}{t} = \frac{8}{14} = 0.57 revolution in one second

so in 1 revolution = \frac{1}{0.57} seconds

so in 1 revolution = 1.75 seconds

so period for 1 revolution is 1.75 seconds

7 0
2 years ago
A man is traveling from the back of a boat to the front of the boat at 2.0 m/s while the boat itself is traveling at 12.0 m/s to
Hatshy [7]

Based on the relative velocity of the man with respect to the boat and the dock:

  • Distance covered in 4.0 seconds relative to the boat  = 8 m
  • Distance covered in 4.0 seconds relative to the dock = 56 m

<h3>What is relative velocity?</h3>

Relative velocity is the velocity of a body relative to another body which serves as a reference point.

Relative velocity is a vector.

Considering the velocity of the man and the boat:

The relative velocity of the man with respect to the boat = 2.0 m/s

Distance covered in 4.0 seconds relative to the boat = 2.0 m/s * 4.0 s

Distance moved = 8 m

Relative velocity of the man with respect to the dock = 12 + 2 = 14 m/s

Distance covered in 4.0 seconds relative to the dock = 14.0 m/s * 4.0 s

Distance moved = 56 m

In conclusion, the relative velocity is velocity with respect to a reference point.

Learn more about relative velocity at: brainly.com/question/24337516

#SPJ1

5 0
1 year ago
What does the thermosphere and stratmosphere have in common
Darya [45]

these include the troposphere (0 to 16 km), stratosphere (16 to 50 km), mesosphere (50 to 80km) and thermosphere (80 to 640km). The boundaries between these four layers are defined by abrupt changes in temperature, and include respectively the tropopause, stratopause and mesopause.

5 0
3 years ago
What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-
sergey [27]

q = -21 * 10^{-6} C

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\

and its sign must be negative so that it will have upward electric force

so it is

q = -21 * 10^{-6} C

The charge of a particle of mass is -21 * 10^{-6} C

Learn more about Free-fall acceleration: brainly.com/question/2165771

#SPJ1

8 0
2 years ago
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