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Likurg_2 [28]
3 years ago
14

A passenger jet flies from one airport to another 1,273 miles away in 2.2 h. find its average speed.

Physics
2 answers:
oee [108]3 years ago
3 0
Speed : distance divide by time . 1273/2.2 = ...

Use calculator .
Shtirlitz [24]3 years ago
3 0

Answer:

V_avg = 578.6364 miles/hr

Explanation:

Given:

- The distance between airports d = 1,273 miles

- The time taken for the flight t = 2.2 hr

Find:

The average speed of the jet

Solution:

- The average speed of the jet is given by V_avg:

                     V_avg = Total distance traveled / Total time

                     V_avg = 1273 / 2.2

                      V_avg = 578.6364 miles/hr

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Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

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The cross sectional area of the solenoid is given as;

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The inductance of the solenoid is given by;

L = \frac{\mu_0 N^2A}{l} \\\\L =  \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

E = 7.078 x 10⁻⁵ J

Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J

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