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Likurg_2 [28]
3 years ago
14

A passenger jet flies from one airport to another 1,273 miles away in 2.2 h. find its average speed.

Physics
2 answers:
oee [108]3 years ago
3 0
Speed : distance divide by time . 1273/2.2 = ...

Use calculator .
Shtirlitz [24]3 years ago
3 0

Answer:

V_avg = 578.6364 miles/hr

Explanation:

Given:

- The distance between airports d = 1,273 miles

- The time taken for the flight t = 2.2 hr

Find:

The average speed of the jet

Solution:

- The average speed of the jet is given by V_avg:

                     V_avg = Total distance traveled / Total time

                     V_avg = 1273 / 2.2

                      V_avg = 578.6364 miles/hr

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