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Readme [11.4K]
3 years ago
15

A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 49 m and acquired a velocity of 30 m/s How long did the burn phase last?
Physics
2 answers:
Nuetrik [128]3 years ago
7 0

Answer:

Explanation:

As the rocket was going up with acceleration due to upthrust by engine we will not take the effect of gravitational acceleration g separately.

Download docx
dusya [7]3 years ago
4 0
I: x = 1/2at²
II: v = at

I+II: x = 1/2a(v²/a²) = 1/2 v²/a

a = 1/2 v²/x

v = 30
x = 49


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Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

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Which are ways to improve the design of this experiment? Check all that apply.
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Answer:

* Experiment with a higher range of materials

* Use a galvanometer.

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Explanation:

This is an experiment of electricity and magnetism, in general the best way to improve the results are:

* Experiment with a higher range of materials

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3 years ago
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If a box is pushed across a floor with a force of 130N. The frictional force acting between the box and the floor is 30N, over a
Sidana [21]
The force acting in the front direction is the 130N.
The frictional force is acting backwards          30N.

1) The net force is 130N - 30N    =  100N

2)  s  = ut + (1/2)at^2             u = 0,  Start from rest,  s = 25m t =5.

25 = 0*5  +  (1/2)* a * 5^2.

25 = 0  +  25/2  * a.

25  =    (25/2)a.      Divide 25 from both sides.

1 =  (1/2)* a.          Cross multiply.

2 = a.

a = 2 m/s^2.

3) Mass of the box
Net Force,  F = ma
                   100 =  m*2.        Divide both sides by 2.
                    
                     100/2  =  m
                       50       =  m.
                        m  = 50 kg.

4)  Final velocity ,   v = u + at.
                                   v  =  0  + 2*5 = 10 m/s.
                                  
   Kinetic Energy,  K  =  (1/2) * mv^2.
                                    =    1/2  * 50 * 10 * 10.
                                    =      2500 J.
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