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NISA [10]
3 years ago
14

Why is it important for a muscle to be attached to a fixed origin at one end and a moving insertion at the other? Discuss how th

is promotes movement, using one of the muscles you observed as an example.
Physics
1 answer:
vlabodo [156]3 years ago
6 0
Muscles function only by contracting. This makes it necessary for one end of the muscle to be fixed and the other mobile.
Take the bicep for example.
Its origin is at the shoulder and its two heads connect to the bones of the forearm, the radius and ulna.
Now, had the muscle not been fixed at one end, and contracted, it would pull both our shoulder and forearm together resulting in an ineffective movement. The desired motion is to lift the forearm (proximal and distal movement) which can only be achieved if the bicep is fixed at the shoulder and allowed to move at the forearm.
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Bumper car A (281 kg) moving
solmaris [256]

use consevation of linear momentum

  • m1v1+m2v2=(M1+M2)V3
  • 281(2.82)+209(-1.72)=(209+281)V2
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  • 432.9=490v3
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4 0
2 years ago
An airplane has a takeoff speed of 62 m/s. assuming a constant acceleration of 1.7 m/s2, what is the minimum length of runway it
UkoKoshka [18]

Data:

u=0 m/s is the initial velocity of the plane

v=62 m/s is the final velocity of the plane (at which the plane takes off)

a=1.7 m/s^2 is the acceleration of the plane

To find the minimum distance S the plane needs to take off, we can use the following equation:

2aS=v^2 -u^2

Re-arranging it and substituting the numbers, we find

S=\frac{v^2-u^2}{2a}=\frac{(62 m/s)^2-0}{2(1.7 m/s^2)}=1131 m

3 0
3 years ago
Two trucks are traveling in the same direction, one going twice as fast as the other. at the end of 6 hours they are 204 miles a
Gemiola [76]
<span>speed of slower=x; distance in 6 hours is 6x
 speed of larger=2x; distance in 6 hours is 12x
 12x-6x=204 miles
</span><span> 6x=204
 x=34 mph slower, 204 miles in 6 hours.
 2x=68 mph, faster, 408 miles in 6 hours, and difference is 204 miles</span>
6 0
4 years ago
Read 2 more answers
A block of ice with mass 5.50 kg is initially at rest on a frictionless, horizontal surface. A worker then applies a horizontal
Yuki888 [10]

Answer:

A) 3.13 m/s

B) 5.34 N

C) W = 26.9 J

Explanation:

We are told that the position as a function of time is given by;

x(t) = αt² + βt³

Where;

α = 0.210 m/s² and β = 2.04×10^(−2) m/s³ = 0.0204 m/s³

Thus;

x(t) = 0.21t² + 0.0204t³

A) Velocity is gotten from the derivative of the displacement.

Thus;

v(t) = x'(t) = 2(0.21t) + 3(0.0204t²)

v(t) = 0.42t + 0.0612t²

v(4.5) = 0.42(4.5) + 0.0612(4.5)²

v(4.5) = 3.1293 m/s ≈ 3.13 m/s

B) acceleration is gotten from the derivative of the velocity

a(t) = v'(t) = 0.42 + 2(0.0612t)

a(4.5) = 0.42 + 2(0.0612 × 4.5)

a(4.5) = 0.9708 m/s²

Force = ma = 5.5 × 0.9708

F = 5.3394 N ≈ 5.34 N

C) Since no friction, work done is kinetic energy.

Thus;

W = ½mv²

W = ½ × 5.5 × 3.1293²

W = 26.9 J

6 0
3 years ago
The motion of a free falling body is an example of __________ motion​
swat32

Answer:

accelerated

Explanation:

The motion of the body where the acceleration is constant is known as uniformly accelerated motion. The value of the acceleration does not change with the function of time.

4 0
3 years ago
Read 2 more answers
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