A bond with elements from B.
Answer:
I think it is 5.6. This is my answer
Answer:
Difference in Twin's Ages = 12.68 years
Explanation:
Using special theory of relativity's time dilation phenomenon, we first find the time that is passed on earth during Lou's trip.
t = t₀/[√(1 - v²/c²)]
where,
t = time measured by the person in relative motion = 1 year
t₀ = time measured by the person at rest = ?
v = speed of relative motion = 0.96 c
c = speed of light
Therefore,
1 year = t₀/[√(1 - 0.96² c²/c²)]
1 year = t₀/[√(1 - 0.9216)]
(1 year)(0.28 year) = t₀
t₀ = 0.28 year
Let,
y = Sue's age
x = Lou's age
so,
x - y = 13.4 years
but, after this trip Lou has aged 1 year, and on earth only 0.28 years passed so, Sue has aged only 0.28 years. Therefore,
x = x + 1
y = y + 0.28
Therefore,
(x + 1 year) - (y + 0.28 year) = 13.4 years
x - y = 13.4 years - 0.72 year
x - y = 12.68 years
<u>Difference in Twin's Ages = 12.68 years</u>
Answer:
0.39 m/s²
Explanation:
From the question,
a = v²/r.................... Equation 1
Where v = velocity, r = radius.
Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.
Substitute thses values into equation 1
a = 9.83²/249.94
a = 96.63/249.94
a = 0.39 m/s²
Hence the acceleration is 0.39 m/s²
