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4 years ago

What happens at a convergent boundary?

2 answers:

5 0

I am not 100% sure on this, but I would have to say A or D. I am sorry I could not give you a definitive answer but there you go!

Natasha_Volkova [10]4 years ago

4 0

I agree the answer is D

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A charge Q is transferred from an initially uncharged plastic ball to an identical ball 24 cm away.The force of attraction is th

xxMikexx [17]

Answer:

The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

Explanation:

Given;

magnitude of the attractive force, F = 17 mN = 0.017 N

distance between the two objects, r = 24 cm = 0.24 m

The attractive force is given by Coulomb's law;

$F = \frac{1}{4\pi \epsilon _0} \times \frac{Q^2}{r^2} = \frac{kQ^2}{r^2} \\\\Q^2 = \frac{Fr^2}{k} \\\\Q = \sqrt{ \frac{Fr^2}{k}} \\\\Q = \sqrt{ \frac{(0.017)(0.24)^2}{9\times 10^9}} \\\\Q = 3.298 \times 10^{-7} \ C$

The charge of 1 electron = 1.602 x 10⁻¹⁹ C

n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

$n = \frac{3.298 \times 10^{-7}}{1.602 \times 10^{-19}} = 2.06 \times 10^{12} \ electrons$

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

4 0

3 years ago

An automobile engine is 15 percent efficient. How many joules of input work are required to produce 15,000 joules of output work

enyata [817]

15,000J/.15% = 100,000 J

If you want to check,
Multiply 100,000 by .15 and you get 15,000 J

5 0

3 years ago

Read 2 more answers

What is a resistor? A battery A light bulb A switch

melomori [17]

The answer is a battery

8 0

3 years ago

A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s. What is the magnitude of the drill’s angular acceleration?

WARRIOR [948]

Answer:

The magnitude of the drills angular acceleration is $-32\pi s^{-2}$ .

The drill makes 50 revolutions before it stops.

Explanation:

The revolutions that the drill makes in 1 second is

$\dfrac{2400\:rev}{60s} =40\:rev/s$

And the angular velocity is

$\omega= \dfrac{40 (2\pi )}{1s}$ (one revolution is $2\pi$ radians)

$\boxed{\omega =80\pi\:s^{-1}}$

Now, the drill comes to a halt in 2.5 s, which means the magnitude of it's angular acceleration is

$a= \dfrac{\Delta \omega}{\Delta s}$

$a=\dfrac{80\pi-0 }{0-2.5s}$

$\boxed{a=-32\pi \:s^{-2}}$

In other words, the magnitude of the angular acceleration is $-32\pi\: s^{-2}.$

Now, we find the angular displacement of the drill which is given by the equation

$\theta = \omega t +\dfrac{1}{2} \alpha t^2$

putting in $\omega = 80\pi s^{-1}$ , $\alpha = -32\pi s^{-2}$ , and $t=2.5s$ , we get:

$\theta = (80\pi s^{-1} *2.5s)+\dfrac{1}{2} (-32\pi s^{-2})(2.5s)^2$

$\theta = 100\pi$

which is

$\dfrac{100\pi }{2\pi } =50\:rev$ (one revolution is $2\pi$ radians)

50 revolutions.

In other words ,the drill makes 50 revolutions before it stops.

3 0

3 years ago

A quality that has magnitude only is a

Helga [31]

<h3>Answer:</h3>

scaler quantity has magnitude only for example mass ,speed,distance,electric current

8 0

4 years ago