Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Answer: 686ft
Step-by-step explanation: 0
A = (45/360)×16^2×pi
A = 32pi
The answer is A 67%.. went over this answer in class so it is right.
Answer:
56% ≤ p ≤ 70%
Step-by-step explanation:
Given the following :
Predicted % of votes to win for candidate A= 63%
Margin of Error in prediction = ±7%
Which inequality represents the predicted possible percent of votes, x, for candidate A?
Let the interval = p
Hence,
|p - prediction| = margin of error
|p - 63%| = ±7%
Hence,
Upper boundary : p = +7% + 63% = 70%
Lower boundary : p = - 7% + 63% = 56%
Hence,
Lower boundary ≤ p ≤ upper boundary
56% ≤ p ≤ 70%
