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VladimirAG [237]
3 years ago
10

Which process results in a chemical change?

Chemistry
1 answer:
mariarad [96]3 years ago
8 0
2) melting an iron bar
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Several bird species feed is a certain species of tree. Each bird species feeds in a different part of the tree. Which statement
Fofino [41]

Answer:

They have adapted to different niches.

Explanation:

due to competition

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What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?
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Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1      :     2           1 : 1

1 mole of Cu  = 63.5 g

1 mole of  H2 = 2g

1 mole  Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from =  (63.5/2)*10 = 317 g of Copper

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3 years ago
There are 3 naturally occurring isotopes of hydrogen and 2
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Answer:

True

Explanation:

Hydrogen has three naturally occuring isotopes and copper has two.

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The part of an atom where nearly whole mass is<br> concentrated is called
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.....is called nucleus which have a positive charge the positive charge in the nucleus is balanced by the negative electrons making an atom neutral

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Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev
liq [111]

Answer: There will be 131.3 tons of SO_{2} that will be generated.


Explanation : We have the data as 72 tons of H_{2}S, O_{2} is 101 tons and H_{2}O as 38 tons.


Conversion of 1 ton to kg will be approximately 907.2 Kg


We have to convert the given data of tons into kg for all;


So, moles of H_{2}S = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X 10^{6} moles

Now, moles of O_{2} = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X10^{6} moles

And, H_{2}O = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X 10^{6} moles


Now, we have to calculate the moles of H_{2}S

so, 1.916 X 10^{6} moles / 2 moles of H_{2}S = 958 X 10^{3}


Now, for O_{2} ;

So, 2.80 X10^{6} moles / 3 moles of O_{2} = 933.3 X 10^{3} moles


Here, we can see that O_{2} is acting as a limiting reactant.


Now, moles of SO_{2} = 2.80 X10^{6} X (2 moles of SO_{2} / 3 moles of O_{2}) = 1.86 X 10^{6}


Now converting this into mass,


Mass = Moles X Molar Mass

Mass = 1.86 X 10^{6} X (64.066 g/mol X 10^{-3} kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of SO_{2}

7 0
3 years ago
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