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VladimirAG [237]
2 years ago
10

Which process results in a chemical change?

Chemistry
1 answer:
mariarad [96]2 years ago
8 0
2) melting an iron bar
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Primary alcohol oxidation products
Yuliya22 [10]

write an equation to represent the oxidation of an alcohol.

identify the reagents that may be used to oxidize a given alcohol.

identify the specific reagent that is used to oxidize primary alcohols to aldehydes rather than to carboxylic acids.

identify the product formed from the oxidation of a given alcohol with a specified oxidizing agent.

identify the alcohol needed to prepare a given aldehyde, ketone or carboxylic acid by simple oxidation.

write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.

The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.

This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.

Oxidizing the different types of alcohols

The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is

Cr2O2−7+14H++6e−→2Cr3++7H2O

3 0
3 years ago
What is the hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4.
Maksim231197 [3]

The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

pH= -log[H+] - (i)

10^-3=H2So4

H+= 2×10-3

here ,

h2so4 ——— 2[H+] + so4^2-

thus [H+]= 2*10^(-3) because hydrogen ion has two moles

pH= -log[H+]

pH= -log(2×10^-3)

pH= 3-log2

pH= 3-log2pH= 2.7

The pH is 2.7

<h3>What is pH?</h3>

PH is the degree of alkalinity and acidicity in a solution.

Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7

Learn more about pH from the link below.

https://brainly.in/question/9937410

4 0
2 years ago
During a synthesis reaction, 1.8 grams of magnesium reacted with 6.0 grams of oxygen. What is the maximum amount of magnesium ox
skelet666 [1.2K]

Answer:

2.9 grams.

Explanation:

  • From the balanced reaction:

<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (1.8 g) of Mg and (6.0 g) of oxygen:

no. of moles of Mg = mass/molar mass = (1.8 g)/(24.3 g/mol) = 0.074 mol.

no. of moles of O₂ = mass/molar mass = (6.0 g)/(16.0 g/mol) = 0.375 mol.

<em>So. 0.074 mol of Mg reacts completely with (0.074/2 = 0.037 mol) of O₂ which be in excess.</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.074 mol of Mg produce → 0.074 mol of MgO.

<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.074 mol)(40.3 g/mol) = <em>2.98 g.</em>

5 0
3 years ago
How long does it take for only one eighth of a sample of radon-222 to remain
Alex17521 [72]
1/8=(1/2)^3 and the half life of radon is 3.8days

Half life is the time it takes for half of any amount of a radioactive substance to decay into something else.

Therefore for a sample of radon to decay to 1/8 of its original amount, it would take 3 x 3.8days=11.4 days
4 0
3 years ago
Help, please!
professor190 [17]

Hi so from what I can see the pizza as a distant or and you just have to convert the grams of glucose into moles. Most teachers ask for this format

7 0
2 years ago
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