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aliina [53]
3 years ago
15

I need help with this question ​

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

2.25×10¯³ mm.

Explanation:

From the question given above, we obtained the following information:

Diameter in micrometer = 2.25 μm

Diameter in millimetre (mm) =?

Next we shall convert 2.25 μm to metre (m). This can be obtained as follow:

1 μm = 1×10¯⁶ m

Therefore,

2.25 μm = 2.25 μm / 1 μm × 1×10¯⁶ m

2.25 μm = 2.25×10¯⁶ m

Finally, we shall convert 2.25×10¯⁶ m to millimetre (mm) as follow:

1 m = 1000 mm

Therefore,

2.25×10¯⁶ m = 2.25×10¯⁶ m /1 m × 1000 mm

2.25×10¯⁶ m = 2.25×10¯³ mm

Therefore, 2.25 μm is equivalent to 2.25×10¯³ mm.

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Dominant traits are traits that more likely to be transferred from a parent to an offspring so scientist use this term dominant.

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What is osmotic pressure of a solution that contains 13.7 g of propyl alcohol (C3H7OH) dissolved in enough water to make 500 mL
azamat

Answer:

Π = iMRT ½

Explanation:

111 g

= 0.033 mol

0.033 mol CaCl2

0.09632 kg solvent

= 0.0344 m

13.7 g x 1 mol C3H7OH

60.10 g

0.5 L

(0.0821 L.atm/K.mol) (300.15K

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How is the evidence from a fire scene collected? What should be avoided?
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3 years ago
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The density of a substance is 17.5 g/mL. Determine the volume (in mL) of 63.6 g of this substance.​
andreyandreev [35.5K]

Answer:

<h2>volume = 3.63 mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

Since we are finding the volume

Making volume the subject we have

<h3>volume =  \frac{mass}{Density}</h3>

From the question

mass = 63.6 g

Density = 17.5 g/mL

Substitute the values into the above formula and solve for the volume

That's

<h3>volume =  \frac{63.6}{17.5}</h3>

We have the final answer as

<h3>volume = 3.63 mL</h3>

Hope this helps you

5 0
3 years ago
A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
Romashka [77]

Answer:

30 μmol/L

Explanation:

<em>A chemist prepares a solution of barium chloride by measuring out 8.9 μmol of barium chloride into a 300mL volumetric flask and filling the flask to the mark with water. </em>

<em> Calculate the concentration in μmol L of the chemist's barium chloride solution. Round your answer to 2 significant digits.</em>

<em />

The chemist has 8.9 μmol of solute (barium chloride) and he adds water until the mark of 300 mL in the container, which is the volume of the solution. We will need the conversion factor 1 L = 1000 mL. The concentration of barium chloride in μmol/L is:

\frac{8.9\mu mol}{300mL} .\frac{1000mL}{1L} =30\mu mol/L

3 0
3 years ago
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