The current in one wire is 5.00<br> a. what is the current in the other wire.

*a small object with a momentum of 6 kg∙m/s to the west approaches head-on a large object at rest. the small object bounces stra

lora16 [44]

1) The change in the momentum of the small object is given by the difference between its final momentum and its initial momentum:
$\Delta p = p_f - p_i$
where $p_f, p_i$ are the final and initial momentum of the small object. Substituting the numbers of the problem, we find
$\Delta p = - 5kg m/s -(6 kg m/s) = -11 kg m/s$
where we put a negative sign in front of pf because the direction of the object after the collision is opposed to its initial direction.

2) The impulse is equal to the product between the force applied to an object and the time interval:
$J= F \Delta t$ (1)
since the force is the product between the mass and the acceration: F=ma, and the acceleration is equal to the change in velocity divided by the time, we can rewrite (1) as
$J=F \Delta t=ma\Delta t=m \frac{\Delta v}{\Delta t} \Delta t = m \Delta v = \Delta p$
So, the impulse is equal to the variation of momentum. Therefore, the impulse exerted on the small object is
$J=\Delta p = -11 kg m/s$

3) We have to find the final momentum of the large object. Initially, its momentum is zero, because it is at rest. Using the law of conservation of momentum,
$p_i + 0 = p_f + P_f$
where $p_f, p_i$ are the final and initial momentum of the small object, while $P_f$ is the final momentum of the large object. By substituting the numbers we had before:
$P_f = p_i - p_f = 6 kg m/s -(-5 kg m/s) = 11 kg m/s$
So, the impulse exerted on the large object is equal to its variation of momentum:
$J= \Delta P = P_f - P_i = 11 kg m/s -0 = 11 kg m/s$

4 0

3 years ago

What is the difference between mass and weight?

I am Lyosha [343]

Mass is the actual amount of material contained in a body and is measured by kg, gm, etc. Whereas weight is the force extorted by the gravity on that object mg. Note that mass is independent of everything but weight is different on earth, moon, etc.

5 0

2 years ago

A laser beam is incident on a plate of glass that is 2.8 cm thick. The glass has an index of refraction of 1.6 and the angle of

Anna11 [10]

Answer:

b = 2.22 cm

Explanation:

The laser hits a point where the origin of the coordinate system is to carry out the measurements. When the ray enters the glass the angle of refraction is given by the equation

n₁ sin θ₁ = n₂ sin θ₂

where n₁ is the index of refraction of air n₁ = 1 and n₂ is the index of refraction of glass n₂ = 1.6

sin θ₂ = n₁ /n₂ sin θ₁

sin θ₂ = 1 / 1.6 sin 36

sin θ₂ = 0.367

θ₂ = sin⁻¹ 0.367

θ₂ = 21.6º

with this angle and trigonometry we can find the distance x that the ray advances before reaching the bottom of the glass plate

tan 21.6 = x / d

where d is the thickness of the glass d = 2.8 cm

x = d tan 21.6

x = 2.8 tan 21.6

x = 1.11 cm

as in the second surface it has a process of reflection the angle of reflection is equal to the angle of incidence θ_reflected = 21.6º, therefore to return to the upper surface recreate the same distance, therefore the total distance is

b = 2x

b = 2 1.11

b = 2.22 cm

8 0

3 years ago

Waht is pascal law?<br>

Murljashka [212]

Answer: Pascal's law says that pressure applied to an enclosed fluid will be transmitted without a change in magnitude to every point of the fluid and to the walls of the container. The pressure at any point in the fluid is equal in all directions.

Explanation:I search it up °-°

3 0

2 years ago

Read 2 more answers

For the circuit shown in the figure(figure 1) find the current through each resistor. Express your answers using two significant

Angelina_Jolie [31]

The current flowing in each resistor of the circuit is 4 A.

<h3>Equivalent resistance of the series resistors</h3>

The equivalent resistance of the series circuit is calculated as follows;

6 Ω and 4 Ω are in series = 10 Ω

5 Ω and 10Ω are in series = 15 Ω

<h3>Effective resistance of the circuit</h3>

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\R = \frac{R_1R_2}{R_1 + R_2} \\\\R = \frac{10 \times 15}{10 + 15} \\\\R = 6 \ ohms$

<h3>Current flowing in the circuit</h3>

V = IR

I = V/R

I = 24/6

I = 4 A

Learn more about resistors in parallel here: brainly.com/question/15121871

8 0

1 year ago

The current in one wire is 5.00 a. what is the current in the other wire.