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mars1129 [50]
3 years ago
13

Two circular rods, one steel and the other copper, are both 0.780 m long and 1.50 cm in diameter. Each is subjected to a force w

ith magnitude 4350 N that compresses the rod. What is the difference in the length of the two rods when compressed?
Physics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

The difference in the length of the two rods when compressed is 5.4\times10^{-5}\ m.

Explanation:

Given that,

Length = 0.780 m

Diameter = 1.50 cm

Force = 4350 N

(a). For steel rod

We know ,

The young modulus for steel rod

Y=2\times10^{11}

Using formula of young modulus

e_{s}=\dfrac{Fl}{AY}

e_{s}=\dfrac{4350\times0.780}{3.14\times(0.75\times10^{-2})^2\times2\times10^{11}}

e_{s}=9.6\times10^{-5}\ m

(b). For copper rod

We know ,

The young modulus for steel rod

Y=1.1\times10^{11}

Using formula of young modulus

e_{c}=\dfrac{Fl}{AY}

e_{c}=\dfrac{4350\times0.780}{3.14\times(0.75\times10^{-2})^2\times1.1\times10^{11}}

e_{c}=1.5\times10^{-4}\ m

The difference in the length of the two rods when compressed is

difference\ in\ length=e_{c}-e_{s}

difference\ in\ length=1.5\times10^{-4}-9.6\times10^{-5}

difference\ in\ length =5.4\times10^{-5}\ m

Hence, The difference in the length of the two rods when compressed is 5.4\times10^{-5}\ m.

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we can rewrite the above equation as :

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P_2 = 17.79 \ bar

Therefore, the exit pressure is 17.79 bar

7 0
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