First one, for instance they become conductors or insulators depending on the temperature!
Answer:
The low side pressure of an A/C system losing vacuum and the pressure rising above zero indicates that there is too much refrigerant in the system.
Explanation:
Considering an A/C system, the condenser fan might be malfunctioning if the low side pressure of the air conditioner is excessive. On the other hand, it's also conceivable that the system has been overcharged with refrigerant.
Stated the scenario that the refrigerant of the system was being recovered, it is an indication that the system is merely overcharged. Even with the engine off, you will notice high pressures.
Either too much oil is present, or there is too much refrigerant in the air conditioning system. In either case, until you let some of that pressure out—ideally, a mechanic should do this—the issue won't go away on its own.
To know more about the pressure scenarios related to AC systems, refer to:
brainly.com/question/17072827
#SPJ4
Answer:
0.488 m
Explanation:
If θ be the angle ladder makes with the plane
cos θ = 1.2 / 5
Tan θ = 4.04
Let the height a person of weight 600 N can climb be h from the ground .
Distance from the base point where ladder touches the floor = h / tanθ
= h / 4.04
Total reaction force = total downward force
R = 200 + 600
800 N
Frictional force = μ R
= .2 x 800
= 160 N
Taking moment of force about the point on the ladder where it touches the floor and balancing them
200 x 1.2 x .5 + 600 x h / tanθ = μ R x 1.2 / tanθ ( reaction at the top point of ladder where it touches the wall is R₁ and
R₁ =μ R )
= 200 x 1.2 x .5 + 600 x h / tanθ = 160 x 1.2 / tanθ
120 - 600 h / 4.04 = 47.52
120 - 47.52 = 600 h / 4.04
72.48= 148.51 h
h = 0.488 m
=
Answer:
x ≤ 3.6913 m
Explanation:
Given
Mrod = 44.0 kg
L = 4.90 m
Tmax = 1450 N
Mman = 69 kg
A: left end of the rod
B: right end of the rod
x = distance from the left end to the man
If we take torques around the left end as follows
∑τ = 0 ⇒ - Wrod*(L/2) - Wman*x + T*Sin 30º*L = 0
⇒ - (Mrod*g)*(L/2) - (Mman*g)*x + Tmax*Sin 30º*L = 0
⇒ - (44*9.8)*(4.9/2) - (69*9.8)*x + (1450)*(0.5)*(4.9) = 0
⇒ x ≤ 3.6913 m
