Answer: T = 93 N
Explanation:
Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.
ΣF = Σma
Mg - mg = Ma + ma
a = g(M - m) / (M + m)
Now looking only at the larger mass as it falls
Mg - T = Ma
T = Mg - Ma
T = Mg - Mg(M - m) / (M + m)
T = Mg(1 -(M - m) / (M + m))
T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))
T = 93 N
or looking only at the smaller mass
T - mg = ma
T = m(g + a)
T = m(g + g(M - m) / (M + m))
T = mg(1 + (M - m) / (M + m))
T = 6.7(9.8)(1 + (16 - 6.7) / (16 + 6.7))
T = 93 N
Answer:
a) v = 45.37 m/s and b) T = 14.4 N
Explanation:
Let's use Newton's second law with centripetal acceleration
F = ma
Let's set a reference system where the x-axis is horizontal and the y-axis is vertical, in that system the only force to decompose is tension, let's use trigonometry
sin 35 = Tₓ / T
cos 35 =
/ T
Tₓ = T sin35
= T cos 35
Y Axis
-W = 0
T cos 35 = W
T = mg / cos 35
X axis
Tₓ = ma
a = v² / r
T sin 35 = m v² / r
(mg / cos 35) sin 35 = m v² / r
g tan 35 = v² / r
v = √ g r tan 35
v = √ (9.8 300 tan 35)
v = 45.37 m / s
b) the tension of the rope is
T = mg / cos 35
T = 1.20 9.8 / cos 35
T = 14.4 N
Answer:
Hello! Your answer would be, A) True
Explanation:
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When u look at something and study it
Answer: Pascal’s principle (apex)
Hope this helps you out!