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V125BC [204]
3 years ago
11

What is the name of the compound that goes with the chemical formula mgcl2

Chemistry
1 answer:
Dimas [21]3 years ago
7 0
Magnesium chloride is the name for the chemical compounds with the formulas MgCl2 and its various hydrates MgCl2(H2O<span>)x. These salts are typical ionic halides, being highly soluble in water. The hydrated magnesium chloride can be extracted from brine or sea water.</span>
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What is the defination of epsom salt?
prisoha [69]
Crystals of hydrated magnesium sulfate used as a purgative or for other medicinal use


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7 0
2 years ago
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Question 3 of 10
ikadub [295]

Answer:

salt water 97%

fresh water 1%

frozen 2%

Explanation:

8 0
2 years ago
HELPP! pls
pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  \frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}

or,

⇒  Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr

⇒                      =\frac{1}{2}\times 4.96

⇒                      =2.48 \ mole

(b)

The limiting reactant is:

= HBr

(c)

The excess reactant is:

= Al

6 0
2 years ago
A) What mass in grams of H20 is needed to react completely with 40.0 g of
Step2247 [10]

Answer:

m_{H_2O}=9.24gH_2O

Explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2}  *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O

Best regards!

7 0
2 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 45.09 g of NaCl in 174.9 g of H2O.
inysia [295]

Answer:

20.3 %  NaCl

Explanation:

Given data:

Mass of solute = 45.09 g

Mass of solvent = 174.9 g

Mass percent of solution = ?

Solution:

Mass of solution = 45.09 g + 174.9 g

Mass of solution = 220 g

The solute in 220 g is 45.09 g

220 g = 2.22 × 45.09

In 100 g solution amount of solute:

45.09 g/2.22 = 20.3 g

Thus m/m% = 20.3 %  NaCl

5 0
3 years ago
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