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shepuryov [24]
2 years ago
7

In a titration experiment, 13.0 mL of an aqueous HCl solution was titrated with 0.2 M NaOH solution. The equivalence point in th

e titration was reached when 11.1 mL of the NaOH solution was added. What is the molarity of the HCl solution? HCl molarity
Chemistry
1 answer:
Ostrovityanka [42]2 years ago
8 0

Answer:

The molarity of the HCl solution is 0.17M

Explanation:

When a titration occurs between an acid and a base it is called neutralization.

The formula to calculate the concentration of the acid is:

Ca*Va=Cb*Vb

where Ca and Cb are the concentrations of the acid and the base respectively and Va and Vb are the volumes of the acid and the base.

As HCl is an acid, solve the equation for Ca:

Ca=\frac{Cb*Vb}{Va}

Replacing values:

Ca=\frac{0.2MNaOH*11.1mLNaOH}{13.0mLHCl}

Ca=0.17M

Therefore the molarity of the HCl solution is 0.17M

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If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show
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4.5 g/L.

Explanation:

  • To solve this problem, we must mention Henry's law.
  • Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
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<em>∴ P₁S₂ = P₂S₁.</em>

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