Sodium hypochlorite is used in iodoform test for the oxidation of alcohol to aldehyde as shown in the image attached:
Here sodium hypochlorite is formed by the reaction of NaOH with I2 that further oxides alcohols to aldehydes.
In a titration experiment, 13.0 mL of an aqueous HCl solution was titrated with 0.2 M NaOH solution. The equivalence point in th
1 answer:
Answer:
The molarity of the HCl solution is 0.17M
Explanation:
When a titration occurs between an acid and a base it is called neutralization.
The formula to calculate the concentration of the acid is:
Ca*Va=Cb*Vb
where Ca and Cb are the concentrations of the acid and the base respectively and Va and Vb are the volumes of the acid and the base.
As HCl is an acid, solve the equation for Ca:
Replacing values:
Therefore the molarity of the HCl solution is 0.17M
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<h3>Answer:</h3>
1.52 × 10⁻¹⁶ nm
<h3>Explanation:</h3>We are given,
Energy = 3.36 × 10⁻¹⁷ Joules
We are required to find the wavelength of light
We are going to use,
The formula, E = hλ/c
Where E is the energy, λ is the wavelength, h is the plank's constant and c is the speed of light.
h = 6.626 × 10^-34 J-s
c = 2.998 × 10^8 m/s
Working
From the formula;
= (3.36 × 10⁻¹⁷ J)(2.998 × 10^8 m/s) ÷ 6.626 × 10^-34 J-s
= 1.52 × 10⁻²⁵ meters
Therefore, the wavelength in m is 1.52 × 10⁻²⁵ m
Conversion
We need to convert m to nm
Conversion factor is 10⁹
Therefore;
1.52 × 10⁻²⁵ m to nm
will be; 1.52 × 10⁻²⁵ m × 10⁹
= 1.52 × 10⁻¹⁶ nm
Thus, the wavelength in nm is 1.52 × 10⁻¹⁶ nm