In a titration experiment, 13.0 mL of an aqueous HCl solution was titrated with 0.2 M NaOH solution. The equivalence point in th
1 answer:
Answer:
The molarity of the HCl solution is 0.17M
Explanation:
When a titration occurs between an acid and a base it is called neutralization.
The formula to calculate the concentration of the acid is:
Ca*Va=Cb*Vb
where Ca and Cb are the concentrations of the acid and the base respectively and Va and Vb are the volumes of the acid and the base.
As HCl is an acid, solve the equation for Ca:
Replacing values:
Therefore the molarity of the HCl solution is 0.17M
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Answer:
.
Explanation:
Based on the electron configuration of this ion, count the number of electrons in this ion in total:
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Each electron has a charge of .
Atoms are neutral and have charge. However, when an atom gains one extra electron, it becomes an ion with a charge of
. Likewise, when that ion gains another electron, the charge on this ion would become
.
The ion in this question has a charge of . In other words, this ion is formed after its corresponding atom gains two extra electrons. This ion has
electrons in total. Therefore, the atom would have initially contained
electrons. The atomic number of this atom would be
.
Refer to a modern copy of the periodic table. The element with an atomic number of is sulphur with atomic symbol
. To denote the ion, place the charge written backwards ("
" for a charge of
) as the superscript of the atomic symbol:
.