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Sav [38]
3 years ago
15

For which solutes dissolved in a liquid is the overall enthalpy of solution exothermic? A-some gases and most solids B- some sol

ids and most gases C-few solids and few gases D- most solids and most gases
Chemistry
2 answers:
lina2011 [118]3 years ago
8 0

Answer:

B

Explanation:

Just took the test

Aleks [24]3 years ago
4 0

Answer:

b

Explanation:

edge 2021

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Julio earns $300 a week working a summer job. The paycheck he deposits in the bank is for $250. Which of these accounts for the
azamat

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theirs a $50 tax with the income hes making

Explanation:

5 0
2 years ago
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A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
lys-0071 [83]

ke prop to v^2


ke1/v1^2=ke2/v2^2


400/50x50=joules/100x100


400x2x2


1600j

8 0
3 years ago
Based on the information above, which statement provides evidence that a chemical reaction has occurred?
Vesna [10]

Answer: Atoms that make up reactants rearrange into new products

Explanation:

A chemical reaction is the process of breaking down the chemical bonds of the reacting substances  which are commonly called as reactants and making new bonds to form new substances commonly called as products.

The products will contain the same atoms as there are in the reactants but the bonds will rearrange to form different substances.

Every chemical reaction is accompanied with absorption or release of energy.

3 0
2 years ago
What is a model that is used to predict possible genotypes and phenotype of offspring?
frutty [35]
This is called the pedigree chart.
7 0
2 years ago
On the basis of the information above, what is the approximate percent ionization of HNO2 in a 1.0 M HNO2 (aq) solution?
enot [183]

Answer:

The answer is "2%"

Explanation:

Equation:

HNO_2\ (aq) \leftrightharpoons  H^{+} \ (aq) + NO_2^{-}\ (aq) \\\\\  K_a = 4.0\times \ 10^{-4}

H^{+}=?

Formula:

Ka = \frac{[H^{+}][NO_2^{-}]}{[HNO_2]}

Let

[H^{+}] = [NO_2^{-}] = x at equilibrium

x^2 = (4.0\times 10^{-4})\times 1.0\\\\x = ((4.0\times 10^{-4})\times 1.0)^{0.5} = 2.0 \times 10^{-2} \  M\\\\

therefore,

[H^{+}] = 2.0\times 10^{-2} \ M = 0.02 \ M

Calculating the % ionization:

= \frac{([H^{+}]}{[HNO_2])} \times 100 \\\\= \frac{0.02}{1}\times 100 \\\\= 2\%\\\\

6 0
2 years ago
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