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Sav [38]
3 years ago
15

For which solutes dissolved in a liquid is the overall enthalpy of solution exothermic? A-some gases and most solids B- some sol

ids and most gases C-few solids and few gases D- most solids and most gases
Chemistry
2 answers:
lina2011 [118]3 years ago
8 0

Answer:

B

Explanation:

Just took the test

Aleks [24]3 years ago
4 0

Answer:

b

Explanation:

edge 2021

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How many fluorine atoms are present in 5.71 g of C2F4? Please explain in steps!
Leya [2.2K]
Molar mass of C= 12g/mol
2C= 2*12g/mol= 24g/mol
Molar Mass of F=19g/mol
4F= 4*19g/mol= 76g/mol
Total molar mass of C2F4 = (24g/mol+76g/mol)= 100g/mol

Now you need to find the moles of Fluorine
Moles= Mass/molar mass
Moles of Fluorine = 5.71g/100g/mol=0.0571mol of Fluorine

To find the number of atoms you multiply moles by Avogadro's number( 6.022*10 ^{23})

So the number of Fluorine atoms= 0.0571* 6.022x10^23= 3.44x10^22 atoms or 3.44 *10^{22} atoms
7 0
3 years ago
We bored<br> Meeting id:333-065-2087<br> Password:5FRgXJ
Juli2301 [7.4K]

Answer:

pls don't post irrelevant questions

Explanation:

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4 0
3 years ago
Read 2 more answers
How many atoms are found in a 15.5 g sample of bismuth?
r-ruslan [8.4K]

Answer:

4.47 x 10²² atoms

Explanation:

Given parameters:

Mass of Bismuth  = 15.5g

Unknown:

Number of atoms  = ?

Solution:

To find the number atoms, first solve for the number of moles in this element first.

  Number of moles  = \frac{mass}{molar mass}    

  Number of moles  = \frac{15.5}{209}    = 0.074mole

So:

        1 mole of a substance contains 6.02 x 10²³ atoms

     0.074 mole of Bismuth will contain 0.074 x 6.02 x 10²³ atoms

                                                          = 4.47 x 10²² atoms

6 0
3 years ago
Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. At 24ºC and an atmospheric pres
Yanka [14]

Answer:

its 0.163 g

Explanation:

From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2​

PO 2 =P t −P H 2 O

​= 760 − 22.4

=  737.6 mmHg

From the ideal gas equation we write.

W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g

6 0
3 years ago
(?)Na2HPO4 → (?)Na4P2O7 + (?)H2O
Akimi4 [234]

Answer: 2,1,1

Explanation: (2)Na2HPO4=(1)Na4P2O7+(1)H20

7 0
4 years ago
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