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3 years ago

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What is the orbital diagram for phosphorus

1 answer:

scoray [572]3 years ago

4 0

<span>The orbital diagram for phosphorus consists of five electrons in the third shell, eight in the second and two in the first shell, closest to the nucleus. The atomic number of phosphorus is 15. This number indicates the total number of electrons.

Ta Da!!!

Just do a little research!!!

Or not you know, that's what we're here for... </span>

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3 years ago

A cell has the reaction Co2+ (aq) + Cd(s) -------> Cd2+ (aq) + Co(s) E0cell = +0.120 V What is Ecell when [Co2+] = 0.00100 M

musickatia [10]

Answer:

USe this Nernst equation and find your required answer

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5 0

3 years ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

8 0

3 years ago