All categories

3 years ago

!DUE SOON PLEASE HELP!

Chemistry

1 answer:

nalin [4]3 years ago

6 0

Answer:

balanced;

unbalanced;

balanced;

Explanation:

CaO + 3C → CaC2 + CO //all elements are balanced

Na + H2O → 2NaOH + H2 //Na is not balanced on the left

4Fe + O2 → 2Fe2O3 //O is not balanced on the left

2Mg + O2 → 2MgO //left is equal to right, balanced

You might be interested in

My question is what is a cell?

frez [133]

The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.

5 0

4 years ago

List 4 physical properties of each of the following:

Bogdan [553]

A piece of paper is thin, slighlty smooth, can be white and smells woody. 500 g of butter has a density of 0.911 g/ml and has a volume thus of 548.85 ml. Butter has a color yellow and smells fatty. A glass of milk has a white color, sour smell and taste and the milk occupies the volume of glass. Candle is waxy, can be long or short, can have colors of different varieties and is cylindrical.

3 0

3 years ago

In a heat engine of 1000 j of heat enters the system and the piston does 500 j of work what is the final internal energy of the

muminat

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

$\Delta U=q+w\\\\U_{final}-U_{initial}=q+w$

where,

$U_{final}$ = final internal energy

$U_{initial}$ = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and $U_{initial}$

initial internal energy = $U_{initial}$ = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

$U_{final}-(2000J)=(1000J)+(500J)$

(4) By solving the terms, we get

$U_{final}-(2000J)=(1000J)+(500J)$

$U_{final}-(2000J)=1500J$

$U_{final}=2000J+1500J$

$U_{final}=3500J$

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J

3 0

4 years ago

According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams

gogolik [260]

Answer:

$m_{HClO_3}=12.7gHClO_3$

Explanation:

Hello,

Considering the reaction:

$3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3$

The molar masses of chlorine and chloric acid are:

$M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol$

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

$m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3$

Best regards.

4 0

4 years ago

Can someone help me plz!!!<br><br> Calculate the mass, in grams, of 2 moles of CaCl2.

Luden [163]

Answer:

222.2 grams of CaCl2 in 2 moles

Explanation:

Mole=given mass/gram mass formula

2moles=x/Gram Mass Formula

(Gram Mass Formula of CaCl2):

Ca=40.1

Cl= 35.5 x 2= 71

-----------------------

GFM=111.1

2 moles = x/111.1 g

x=222.2

7 0

4 years ago

Read 2 more answers