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3 years ago

An order for ampicillin is 45 mg/kg of body mass. Calculate the dosage of ampicillin in g/lb of body weight.

Chemistry

1 answer:

lawyer [7]3 years ago

7 0

Answer:

0.020g/lb

Explanation:

We start off with 45 mg/kg.

Let's convert the mg to g first to get half the units correct.

1g = 1000mg

Therefore 45mg = 0.045g.

Now we're at 0.045g/kg.

Next we need to convert the kg to lbs.

1 kg = 2.20462262 lbs.

therefore we need to divide 0.045 by 2.20462... to get g/lbs

This gives 0.02041165667 g/lb.

We need this to 2SF, so round to 0.020g/lb

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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o

statuscvo [17]

Answer: The value of $K_{eq}$ is 0.044

Explanation:

We are given:

Initial moles of methane = $4.10\times 10^{-2}mol=0.0410moles$

Initial moles of carbon tetrachloride = $6.51\times 10^{-2}mol=0.0651moles$

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of methane = $\frac{0.0410}{1.00}=0.0410M$

Concentration of carbon tetrachloride = $\frac{0.0651}{1.00}=0.0651M$

The given chemical equation follows:

$CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)$

Initial: 0.0410 0.0651

At eqllm: 0.0410-x 0.0651-x 2x

We are given:

Equilibrium concentration of carbon tetrachloride = $6.02\times 10^{-2}M=0.0602M$

Evaluating the value of 'x', we get:

$\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M$

Now, equilibrium concentration of methane = $0.0410-x=[0.0410-0.0049]=0.0361M$

Equilibrium concentration of $CH_2Cl_2=2x=[2\times 0.0049]=0.0098M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044$

Hence, the value of $K_{eq}$ is 0.044

8 0

3 years ago

5.) A spring with a spring constant of 500 n/m is stretched 1 meter in

Ymorist [56]

Answer:

250J

Explanation:

Given parameters:

Spring constant = 500N/m

Extension = 1m

Unknown:

Elastic potential energy = ?

Solution:

The elastic potential energy of a body is the energy stored within an elastic string.

EPE = $\frac{1}{2}$ k e²

k is the spring constant

e is the extension

Now;

EPE = $\frac{1}{2}$ x 500 x 1² = 250J

4 0

3 years ago

What is the purpose of the plasma membrane?

ollegr [7]

It protects the cell and allows certain material in and out of the cell

5 0

3 years ago

Read 2 more answers

Question 9

Natasha2012 [34]

Answer:

1000 or 250

Explanation:

500x2=1000

500/2=250

5 0

2 years ago

How many grams of sulfur would be a typical amount in a 60.kg adult?

Nadusha1986 [10]

The answer is 180g. Sulfur composes approximately 0.3% of the human body composition. Therefore for a 60kg human, then the amount of sulfur in their body would be (0.3*60)/100 =0.18kg = 180g. Sulfur is mostly found in proteins since it’s a major element that is used in the formation of protein bonds like sulfur bridges etcetera.

6 0

3 years ago