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marysya [2.9K]
3 years ago
12

Compute (3/4)*(8/9)*(15/16)*(24/25)*(35/36)*(48/49)*(63/64)*(80/81)*(99/100) Express your answer in the simplest way possible. (

Suggestion: First, try computing 3/4*8/9 then 3/4*8/9*15/16 and so on. Look for patterns.
Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}

Step-by-step explanation:

Given

(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100})

Required

Simplify

For clarity, group the expression in threes

((\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

Evaluate the first group [Divide 8 by 4]

((\frac{3}{1})*(\frac{2}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

[Divide 9 by 3]

((\frac{1}{1})*(\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

((\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

[Divide 15 by 3]

((\frac{2}{1})*(\frac{5}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

[Divide 16 by 2]

((\frac{1}{1})*(\frac{5}{8}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

(\frac{5}{8})*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

Evaluate the second group [Divide 35 and 25 by 5]

(\frac{5}{8})*((\frac{24}{5})*(\frac{7}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

[Divide 49 by 7]

(\frac{5}{8})*((\frac{24}{5})*(\frac{1}{3})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

[Divide 24 by 3]

(\frac{5}{8})*((\frac{8}{5})*(\frac{1}{1})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

(\frac{5}{8})*((\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

Merge the first and second group

((\frac{5}{8})*(\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

(1*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))

Evaluate the last group [Divide 99 by 9]

(\frac{4}{7})*((\frac{63}{64})*(\frac{80}{9})*(\frac{11}{100}))

[Divide 63 by 9]

(\frac{4}{7})*((\frac{7}{64})*(\frac{80}{1})*(\frac{11}{100}))

[Divide 64 and 80 by 8]

(\frac{4}{7})*((\frac{7}{8})*(\frac{10}{1})*(\frac{11}{100}))

[Divide 10 and 4 by 2]

(\frac{4}{7})*((\frac{7}{4})*(\frac{5}{1})*(\frac{11}{100}))

[Divide 100 by 5]

(\frac{4}{7})*((\frac{7}{4})*(\frac{1}{1})*(\frac{11}{20}))

(\frac{4}{7})*((\frac{7}{4})*(\frac{11}{20}))

(\frac{4}{7})*(\frac{7}{4})*(\frac{11}{20})

1*(\frac{11}{20})

\frac{11}{20}

Hence;

(\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}

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The product of −3 1/4 and −1 1/2  as a mixed number is 4\frac{7}{8}.

The product of −3 1/4 and −1 1/2  as a simplified form is \frac{39}{8}

<h3>What is products and mixed numbers?</h3>

Thew products between two terms can be described as the multiplication operation of the the two terms to give a term which is been performed by the use of the operation sign (*) between the two terms.

The mixed number can be defined as the numbers that contains whole numbers as well as the denominators and numerator.

It should be noted that the product of −3 1/4 and −1 1/2  can be done as (-3\frac{1}{4}  * -1\frac{1}{2}  = -\frac{13}{4} * \frac{-3}{2}  = \frac{39}{8} = 4\frac{7}{8}

Read more on mixed number here: brainly.com/question/21610929

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Answer:

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Step-by-step explanation:

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