Answer:
a) The heat which we supply to water during boiling is used to overcome these forces of attraction between the particles so that they become totally free and change into a gas. This latent heat does not increase the kinetic energy of water particles and hence no rise in temperature takes place during the boiling of water.
b) Steam produces more severe burns than boiling water even though both are at 100oC because steam contains more heat, in the form of latent heat, than boiling water.
Explanation:
i hope this will help u
Answer:fH = - 3,255.7 kJ/mol
Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.
Qsystem + Qcombustion = 0
Qsystem = heat capacity*ΔT
10000*(25.000 - 20.826) + Qc = 0
Qcombustion = - 41,740 J = - 41.74 kJ
So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:
n = mass/molar mass = 1/ 78
n = 0.01282 mol
fH = -41.74/0.01282
fH = - 3,255.7 kJ/mol
Answer:
7.14 × 10^(-58) m
Explanation:
We are given;
Energy; E = 2.78 x 10^(32) J
Formula to find this energy is;
E = hc/λ
Where;
E is energy
h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s
c is speed of light with a constant value of 3 × 10^(8) m/s
λ is wavelength
Making λ the subject, we have;
λ = hc/E
λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))
λ = 7.14 × 10^(-58) m
Answer:
Break up the soil to increase the number of pores should be your answer.
Explanation:
If you do that it will increase the amount of water in the plant.
16 protons and 18 electrons gives the atom a -2 charge because there are 2 more electrons than protons. If it were 16 protons and 16 electrons, the charge would be 0 or neutral.
