Breakdown of energy rich molecules without oxygen present. In human muscles, it is the same equation wise as lactic acid fermentation.

![$$p H-p K_a+\log \frac{\left[A^{-}\right]}{[H A]}$$](https://tex.z-dn.net/?f=%24%24p%20H-p%20K_a%2B%5Clog%20%5Cfrac%7B%5Cleft%5BA%5E%7B-%7D%5Cright%5D%7D%7B%5BH%20A%5D%7D%24%24)
![$$Where $\left[A^{-}\right]-[H A]$, so $\log \frac{\left[A^{-}\right]}{[H A]}-\log 1-0_{\text {so ... }}$$$](https://tex.z-dn.net/?f=%24%24Where%20%24%5Cleft%5BA%5E%7B-%7D%5Cright%5D-%5BH%20A%5D%24%2C%20so%20%24%5Clog%20%5Cfrac%7B%5Cleft%5BA%5E%7B-%7D%5Cright%5D%7D%7B%5BH%20A%5D%7D-%5Clog%201-0_%7B%5Ctext%20%7Bso%20...%20%7D%7D%24%24%24)
pH-pKa







<h3>What is a conjugate acid and base pair?</h3>
An acid-base pair that differs by one proton is referred to as a conjugate pair. A conjugate acid-base pair is a pair of substances that can both absorb and donate hydrogen ions to one another. A proton is added to the compound to create the conjugate acid, and a proton is taken out to create the conjugate base. When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created.
To learn more about conjugate acid and base pair, visit;
brainly.com/question/10468518
#SPJ4
The correct option is B.
To determine the formula of a new substance, one has to first determine the percentage composition of each of the elements in the compound. The ratios of each element in the compound will give information about how much of each element is present. The formula of the element will be given based on the quantity of each constituent in the compound.
D. The volume of a new substance has increased.
Explanation:
It is known that relation between wavelength and frequency is as follows.

where,
= wavelength
c = speed of light = 
[/tex]\nu[/tex] = frequency
It is given that frequency is
. Hence, putting this value into the above formula and calculate the wavelength as follows.


= 
or, = 
Thus, we can conclude that wavelength of given radiation is
.