Answer:
Option D. 3 ppm isopropanol
Explanation:
The following data were obtained from the question:
Mass of isopropanol = 6 mg
Mass of water = 2 Kg
Isopropanol concentration =?
The isopropanol concentration can be obtained as follow:
Concentration = mass isopropanol / mass of water
Isopropanol concentration = 6 mg / 2 kg
Isopropanol concentration = 3 mg/Kg
Finally, we shall convert 3 mg/Kg to ppm. This can be obtained as follow:
1 mg/Kg = 1 ppm
Therefore,
3 mg/Kg = 3 ppm
Thus, we can conclude that the concentration of isopropanol is 3 ppm.
