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Lady bird [3.3K]
3 years ago
6

Carmen rides her bicycle at a constant rate to the market. When she rides her bicycle back home along the same route, she bikes

at three-quarters the rate she biked to the market. At any given time, t, the distance biked can be calculated using the formula d = rt, where d represents distance and r represents rate. If the trip home takes 12 minutes longer than the trip to the market, how many minutes does it take Carmen to bike home?
Mathematics
2 answers:
lianna [129]3 years ago
8 0
It can be easily assumed that most information's are already given in the question. Based on those information's, the answer can be deduced.

rt = [(3/4)r] * (t + 12)
4rt = 3r (t + 12)
4rt = 3rt + 36r
4rt - 3rt = 36r
rt = 36r
t = 36
From the above deduction we can conclude that the time taken by Carmen to ride to the market is 36 minutes
Then
Time taken by Carmen to ride home = 36 + 12 = 48 minutes
marta [7]3 years ago
6 0

Answer:

D, 48

Step-by-step explanation:

edge2020

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Absolute Value

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Select all the statements that are true.
alexgriva [62]

Answer:

The product of 8x(5x−6) is 40x^2−48x

The product of (x−3)(5x−6) is 5x^2−21x+18

Step-by-step explanation:

<u><em>Verify each option</em></u>

Part 1) The product of 8x(5x−6) is 40x^2−48x

we have

8x(5x-6)

Applying distributive property

8x(5x)-8x(6)\\40x^2-48x

Compare with the given value

40x^2-48x=40x^2-48x

therefore

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Part 2) The product of −4x(2x2+1) is −8x^3−5x

we have

-4x(2x^{2}+1)

Applying distributive property

-4x(2x^{2})-4x(1)\\-8x^3-4x

Compare with the given value

-8x^3-4x \neq -8x^3-5x

therefore

The statement is not true

Part 3) The product of (x−3)(5x−6) is 5x^2−21x+18

we have

(x-3)(5x-6)

Applying distributive property

x(5x)-x(6)-3(5x)+3(6)\\5x^2-6x-15x+18\\5x^2-21x+18

Compare with the given value

5x^2-21x+18=5x^2-21x+18

therefore

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we have

(2x+3)(x^2+3x-5)

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Compare with the given value

2x^3+9x^2-x-15 \neq 2x^3+9x^2+9x-25

therefore

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