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FrozenT [24]
3 years ago
7

The Great Pyramid of Giza is an example of a square pyramid and is the last

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

The surface area of the pyramid is 466,137 squared cubits

Step-by-step explanation:

This is simply asking us to find the surface area of the square based pyramid with the given dimensions.

The first thing we need to know is the principle for finding the surface area of such pyramidal shapes. To get the surface area of a pyramid, we will have to add the base area to the area of the side faces ( lateral area)

The base area of the square based pyramid, will be the same as the area of a square which is = 453 cubits X 453 cubits =205209 cubits^{2}

The lateral area has already been given to us as 260,928 squared cubits.

The surface area of the pyramid is 260,928 + 205209 = 466137 squared cubits

Hence, the surface area of the pyramid is 466137 squared cubits

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Students at a major university are complaining of a serious housing crunch. Many of the university's students, they complain, ha
Andrews [41]

Answer:

1) Between 12.5 miles and 21.7 miles.

2) b) 75%

3) c) 95%

4) Between 13.7 miles and 20.5 miles.

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Chebyshev Theorem:

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by P = 100(1 - \frac{1}{k^{2}}).

1) According to Chebyshev's theorem, at least 36% of the commute distances lie between miles and miles.

Within k standard deviations of the mean, and k is found when P = 36. So

P = 100(1 - \frac{1}{k^{2}})

36 = 100 - \frac{100}{k^2}

\frac{100}{k^2} = 64

64k^2 = 100

k^2 = \frac{100}{64}

k = \sqrt{\frac{100}{64}}

k = \frac{10}{8}

k = 1.25

Within 1.25 standard deviations of the mean.

1.25*3.7 = 4.6 miles

17.1 - 4.6 = 12.5 miles

17.1 + 4.6 = 21.7 miles

Between 12.5 miles and 21.7 miles.

2) According to Chebyshev's theorem, at least of the commute distances lie between 9.7 miles and 24.5 miles.

17.1 - 9.7 = 24.5 - 17.1 = 7.4 miles, so within 2 standard deviations of the mean, which is 75%, option B.

3) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately of the commute distances lie between 9.7 miles and 24.5 miles.

Within 2 standard deviations of the mean, by the Empirical Rule, which is 95%, option c.

4) Suppose that the distribution is bell-shaped. According to the empirical rule, approximately 68% of the commute distances lie between miles and miles.

Within 1 standard deviation of the mean.

17.1 - 3.4 = 13.7

17.1 + 3.4 = 20.5

Between 13.7 miles and 20.5 miles.

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Sub in 4 for x and multiply so it would be 112 + 30 + 16 which is 158
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