White dwarfs, the energy will all be used and it will begin to shrink.
Answer:
V = I(R+r)
Explanation:
According to ohms law, the current (I) passing through a metallic conductor at constant temperature is directly proportional to the potential difference (V) across its end.
Mathematically, V= IR where V is the potential difference
I is the current
R is resistance
Given emf (E) = IRt... (1)
where E is the emf
Rt is the total equivalent resistance
The external resistance Rv is connected in series with the internal resistance 'r' to give total equivalent resistance Rt = (R+r)
Substituting in equation 1
E = I(R+r)
The equivalent potential difference V = I(R+r)
Answer:
The value is 
Explanation:
From the question we are told that
The radius of the inner conductor is 
The radius of the outer conductor is 
The potential at the outer conductor is 
Generally the capacitance per length of the capacitor like set up of the two conductors is
![C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}](https://tex.z-dn.net/?f=C%3D%20%5Cfrac%7B2%20%2A%20%5Cpi%20%2A%20%5Cepsilon_o%20%7D%7B%20ln%20%5B%5Cfrac%7Br_2%7D%7Br_1%7D%20%5D%7D)
Here 
is the permitivity of free space with value 
=> ![C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}](https://tex.z-dn.net/?f=C%3D%20%5Cfrac%7B2%20%2A%20%203.142%20%20%2A%208.85%2A10%5E%7B-12%7D%20%20%7D%7B%20ln%20%5B%5Cfrac%7B0.003%7D%7B0.001%7D%20%5D%7D)
=> 
Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge
Generally the line charge density of the outer conductor is mathematically represented as
=> 
=> 
Generally the surface charge density is mathematically represented as
here 
=> 
=>
A force is a push or pull upon an object resulting from the object's interaction with another object.
The number of ocean waves that pass a buoy in one second is the frequency of the <span>wave. The crest of a transverse wave is its highest point. </span>
