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3 years ago

How many hydrogen atoms are in representative particle of each substance?Al(OH)3

Chemistry

1 answer:

Drupady [299]3 years ago

3 0

Answer:

There are 3 hydrogen atoms in the representative particle of Al(OH)₃

Explanation:

Al(OH)₃ is the chemical formula for the representative particle of aluminum hydroxide.

Since Al (aluminum) has not any subscript associated, it is understood that there is 1 atom of aluminum in each representative particle of Al(OH)₃.

Since the subscript 3 is after a parenthesis, it affects all the atoms that are inside such parenthesis. This leads to:

- there are 3 atoms of oxygen in each representative particle of Al(OH)₃, and

- there are 3 atoms of hydrogen in each representative particle of Al(OH)₃.

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3 years ago

The Half-Life of Pa-234 is 6.75 hours. How much (what fraction) of a sample of this isotope remains after 20.25 hours?

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3 years ago

27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a

jok3333 [9.3K]

Answer : The volume of the cube is, $21.88cm^3$

Solution : Given,

Density of nickel = $8.91g/cm^3$

Number of nickel atoms = $2\times 10^{24}$

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, $6.022\times 10^{23}$ atoms form 1 mole of nickel

So, $2\times 10^{24}$ atoms form $\frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321$ moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

$\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}$

$\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g$

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

$Density=\frac{Mass}{Volume}$

$8.91g/cm^3=\frac{194.94g}{Volume}$

$Volume=21.88cm^3$

Therefore, the volume of the cube is, $21.88cm^3$

4 0

3 years ago

Predict the aldol product when the following ketone undergoes self-condensation in the presence of NaOH. Do not show the dehydra

Anit [1.1K]

Answer:

β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.

Explanation:

When acetaldehyde is treated with dil.NaOH it undergoes self condensation as it contains alpha-hydrogen atom in its compound forming β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal. This compound upon further heating will eliminate a molecule of water forming aldol condensation product namely Crotonaldehyde Or But-2-en-al. see the diagram attached.

5 0

3 years ago