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EastWind [94]
3 years ago
5

How to Balance __MgF2 + __Li2CO3 + __ LiF

Chemistry
1 answer:
Andru [333]3 years ago
7 0
__MgF2 + __Li2CO3 + __ 2LiF
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Does sauce either rhyme with avoid, crowd,false,hall,or hawk​
Alenkinab [10]

Answer:

false

Explanation:

the last letters in the words ryhme and make similiar sounds unlike the other words

7 0
3 years ago
A piece of metal with a mass of 147g and a volume of 21ml. Calculate the density of the metal.
kipiarov [429]

Answer:

density of a piece of metal = 7 gr/ml

Explanation:

See the file please

3 0
3 years ago
Read 2 more answers
A block of aluminium occupies a volume of 11.1 mL and weighs 43 g. What is it's density? Give answer with one decimal.
horrorfan [7]

Answer:

<h2>Density = 3.9 g/ mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 43 g

volume = 11.1 mL

Substitute the values into the above formula and solve for the density

That's

Density =  \frac{43}{11.1}  \\  = 3.873873...

We have the final answer as

Density = 3.9 g/ mL to one decimal place

Hope this helps you

8 0
4 years ago
The chemical equation below shows the reaction between tin (Sn) and hydrogen fluoride (HF). Sn + 2HF mc017-1.jpg SnF2 + H2 The m
Sergio [31]
Tin and Hydrofluoric Acid reacts as shown,

<span>                              Sn  +  2 HF    </span>→    SnF₂<span>  +  H</span>₂

According to Equation,

40.02 g (2 Moles) HF Required  =  <span>1 Mole of Sn for complete Reaction

So,
              40 g of HF will require  =  X Moles of Sn

Solving for X,
                                       X  =  (40 g </span>× 1 Mole) ÷ 40.02 g

                                       X  =  0.999 Moles  ≈  1 Mole
Result:
            40 g 
of HF requires 1 Mole of Tin (Sn) for complete Reaction to produce SnF₂ and H₂.
7 0
3 years ago
Read 2 more answers
Will IO- and NaOH form a buffer?​
evablogger [386]

Answer:

this is the answer for will NaOH be a buffer

Explanation:

The compound CH 3NH 3Cl is a salt made from that weak base, so the combination of these two solutes would make a buffer solution. NH 3 is a weak base, but NaOH is a strong base. The combination of these two solutes would not make a buffer solution

4 0
4 years ago
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