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Kaylis [27]
3 years ago
9

3. Calculate the momentum of a 1200kg car with a velocity of 25m/s.

Physics
1 answer:
antiseptic1488 [7]3 years ago
4 0

momm=massxvelocity

momm=1200x2.5=120x25=600x5=3000kgm/s

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A quarterback passes a football from height h = 2.1 m above the field, with initial velocity v0 = 13.5 m/s at an angle θ = 32° a
SOVA2 [1]

Answer:

a)    x = v₀² sin 2θ / g

b)    t_total = 2 v₀ sin θ / g

c)    x = 16.7 m

Explanation:

This is a projectile launching exercise, let's use trigonometry to find the components of the initial velocity

        sin θ = v_{oy} / vo

        cos θ = v₀ₓ / vo

         v_{oy} = v_{o} sin θ

         v₀ₓ = v₀ cos θ

         v_{oy} = 13.5 sin 32 = 7.15 m / s

         v₀ₓ = 13.5 cos 32 = 11.45 m / s

a) In the x axis there is no acceleration so the velocity is constant

         v₀ₓ = x / t

          x = v₀ₓ t

the time the ball is in the air is twice the time to reach the maximum height, where the vertical speed is zero

          v_{y} = v_{oy} - gt

          0 = v₀ sin θ - gt

          t = v_{o} sin θ / g

         

we substitute

       x = v₀ cos θ (2 v_{o} sin θ / g)

       x = v₀² /g      2 cos θ sin θ

       x = v₀² sin 2θ / g

at the point where the receiver receives the ball is at the same height, so this coincides with the range of the projectile launch,

b) The acceleration to which the ball is subjected is equal in the rise and fall, therefore it takes the same time for both parties, let's find the rise time

at the highest point the vertical speed is zero

          v_{y} = v_{oy} - gt

          v_{y} = 0

           t = v_{oy} / g

           t = v₀ sin θ / g

as the time to get on and off is the same the total time or flight time is

           t_total = 2 t

           t_total = 2 v₀ sin θ / g

c) we calculate

          x = 13.5 2 sin (2 32) / 9.8

          x = 16.7 m

5 0
3 years ago
A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of
miskamm [114]

Answer:

q = 0.036 C

Explanation:

Given that,

Current passes through a defibrillator, I = 18 A

Time, t = 2 ms

We need to find the charge moved during this time. We know that,

Electric current = charge/time

q=It

Put all the values,

q=18\times 0.002\\\\q=0.036\ C

So, 0.036 C of charge moves during this time.

8 0
3 years ago
What elements are not a major category of elements on the periodic table
lana66690 [7]

Answer:

Group and Periods of the Periodic Table of Elements. The three major groups on the Periodic Table are the metals, nonmetals and metalloids. Elements within each group have similar physical and chemical properties.

3 0
2 years ago
How does changing the lengthy but not the height of an inclined plane affect the work done to lift a load? PLZ HELP ME NOW'
Serhud [2]

Answer: Work Done would remain same.

Let us assume that the velocity is constant while taking the load up the inclined plane. Then, the kinetic energy would remain the same. This is because kinetic energy is dependent on velocity (K.E.=\frac{1}{2}mv^2). If that is constant, the kinetic energy would remain same. The potential energy is dependent on the height(P.E.=mgh). If the height is changed, then potential energy varies. In the question, it is mentioned that without changing the height, the length of the inclined plane is changed. Therefore, the potential energy would be same as before.

We know, work done is equal to potential energy plus kinetic energy. Since there is no change in any of these, the required work done would not change.


4 0
3 years ago
A 75.0-kg person climbs stairs, gaining 2.50 m in height. Find the work done to accomplish this task.
ololo11 [35]

Answer:

W=1837.5J

Explanation:

A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:

W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d

In this case, we have:

F=mg\\h=dcos\theta

So, replacing this:

W=mgh\\W=75kg*9.8\frac{m}{s^2}*2.5m\\W=1837.5J

4 0
4 years ago
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