Answer:
Δx = 2m
Explanation:
From the given information:
De la información dada:
El desplazamiento ocurrió en un vector que se mueve desde una posición inicial particular hasta el final.
Entonces, supongamos que el desplazamiento es D;
Luego:
D = (7,5 ) - (5,7)
D = (2, -2)
Por lo tanto, el valor del desplazamiento de la coordenada x; Δx = 2m
Answer:
The distance is 1.026 m.
Explanation:
mass of rod, M = 1.23 kg
Length, L = 1.25 m
mass, m = 10 kg
Time period, T = 2 s
Let the distance is d.
The formula of the time period is given by

The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
Learn more about angular momentum here:
brainly.com/question/7538238
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I think it is c I'm only in 7th grade but I'm pretty sure that the answer is c
Answer and Explanation:
Based on the given information, the formula and the computation is given below:
a. The rotational inertia of the hoop is shown below:



= 0.73 × (0.36 + 0.1444)
= 0.368 
b. Now the rotational kinetic energy is


= 36.58 J
We simply applied the above formula for rotational inertia and rotational kinetic energy in order to reach with the correct answer