The time of motion of the object at the given speed and distance is 4 seconds.
<h3>Time of motion of the object</h3>
The time of motion of the object is calculated as follows;
t = d/v
where;
- d is distance = 10 m
- v is speed = 2.5 m/s
- t is time of motion
t = 10/2.5
t = 4 s
Thus, the time of motion of the object at the given speed and distance is 4 seconds.
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It depends on the objects chemical composition.
Answer:
25 m
Explanation:
The relationship between Velocity, distance and time is given as
S = v/t........................... Equation 1
Where S = average velocity of the car, d = distance covered by the car, t = time
Making d the subject of the equation,
d = vt.................... Equation 2
Given: v = 6.25 m/s, t = 4.00 s.
Substitute into equation 2,
d = 6.25(4)
d = 25 m.
Hence, the distance traveled by the car = 25 m
Answer:
(A) = 2.13 s
(B) = 0.47 Hz
(C) = 0.25 m
(D) = 0.74 m/s
Explanation:
number of oscillations (n) = 15
time (t) = 32 secs
start point (L1) = 13 cm = 0.13 m
End point (L2) = 63 cm = 0.63 m
(A) period = time / number of oscillation
= 32 / 15 = 2.13 s
(B) frequency = 1 / period
= 1 / 2.13 = 0.47 Hz
(C) Amplitude = 0.5 ( L2 - L1 )
= 0.5 ( 0.63 - 0.13 )
= 0.25 m
(D) max speed = (2π / T) x A
= (2π / 2.13) x 0.25
= 0.74 m/s
