Answer:
The representation of a chemical reaction in the form of substances is known as a chemical equation. The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation.
The Law of conservation of mass governs the balancing of a chemical equation.
According to this law, mass can neither be created nor be destroyed in a chemical reaction and obeying this law total mass of the elements or molecules present on the reactant side should be equal to the total mass of elements or molecules present on the produc
<h3>
<u>Answer;</u></h3>
= 5.102 m
<h3><u>Explanation;</u></h3>
The total energy, i.e. sum of kinetic and potential energy, is constant.
That is; E = KE + PE
Initially, PE = 0 and KE = 1/2 mv^2
At maximum height, velocity=0, thus, KE = 0 and PE = mgh
Since, total energy is constant (KE converts to PE when the ball is rising).
Therefore, KE = PE
or, 1/2 mv^2 = mgh
or, h = v^2 /2g
= 10^2 / (2x9.8)
=<u> 5.102 m</u>
Answer:
Heat transfer during the process = 0
Work done during the process = - 371.87 KJ
Explanation:
Initial pressure
= 0.02 bar
Initial temperature
= 200 K
Final pressure
= 0.14 bar
Gas constant for helium R = 2.077 
This is an isentropic polytropic process so temperature - pressure relationship is given by the following formula,
= ![[\frac{P_{2} }{P_{1} } ]^{\frac{\gamma - 1}{\gamma} }](https://tex.z-dn.net/?f=%5B%5Cfrac%7BP_%7B2%7D%20%7D%7BP_%7B1%7D%20%7D%20%5D%5E%7B%5Cfrac%7B%5Cgamma%20-%201%7D%7B%5Cgamma%7D%20%7D)
Put all the values in above formula we get,
⇒
= ![[\frac{0.14 }{0.02 } ]^{\frac{1.4 - 1}{1.4} }](https://tex.z-dn.net/?f=%5B%5Cfrac%7B0.14%20%7D%7B0.02%20%7D%20%5D%5E%7B%5Cfrac%7B1.4%20-%201%7D%7B1.4%7D%20%7D)
⇒
= 1.74
⇒
= 348.72 K
This is the final temperature of helium.
For isentropic polytropic process heat transfer to the system is zero.
⇒ ΔQ = 0
Work done W = m × (
-
) × 
⇒ W = 1 × ( 200 - 348.72 ) × 
⇒ W = 371.87 KJ
This is the work done in this process. here negative sign shows that work is done on the gas in the compression of gas.
I don’t understand the question I’m really sorry:/.