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lina2011 [118]
3 years ago
8

Long division 150 divided by 12

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
8 0
150 ÷ 12

12 I 150

there is no twelve in one, so it is just zero
       0
12 I 150

In 15, there is 1 twelve, because 12 × 1 = 12
       01
12 I 150
      -12
       030

There are 2 twelves in 30, because 2 × 12 = 24
       012
12 I 150
      -12
       030
        -24
         06

Put a decimal point after the quotient and 150 to continue from the remainder
       012.
12 I 150.
      -12
       030
       -24
        060

There are exactly 5 twelves in 60, 5 × 12 = 60
       012.5
12 I 150.0
      -12
       030
        -24
          060
           -60
            00     no remainder

150 ÷ 12 = 12.5

Nataliya [291]3 years ago
7 0
150÷12 = 
CORRECT SOLUTION:
15 goes into 12 once so 150÷12 = 1
The remainder is 3 because 15-12 =3
30÷12 = 2
The remainder is 6 because 30-24=6
ad a decimal point and a 0                                                                         60÷12=5
<span>CORRECT ANSWER: 12.5</span>

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A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 ​respon
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99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14​% chose chocolate​ pie, and the margin of error was given as plus or minus ±3 percentage points. 

The pivotal quantity for the confidence interval for the population proportion is given by;

                            P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who chose chocolate​ pie = 14%

            n = sample of adults = 500

            p = true proportion

Now, the 99% confidence interval for p =  \hat p \pm Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.03 for 99% interval.

<u>So, 99% confidence interval for p</u>  =  0.14 \pm2.5758  \times \sqrt{\frac{0.14(1-0.14)}{500} }

                                                        = [0.14 - 0.03 , 0.14 + 0.03]

                                                        = [0.11 , 0.17]

Similarly, <u>80% confidence interval for p</u>  =  0.14 \pm 1.2816  \times \sqrt{\frac{0.14(1-0.14)}{500} }

Here, \alpha = 20% so  (\frac{\alpha}{2}) = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  = 0.02 for 80% interval.

So, <u>80% confidence interval for p</u>  =  [0.14 - 0.02 , 0.14 + 0.02]

                                                           =  [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

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