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LenaWriter [7]
2 years ago
13

What type of composition does an igneous rock have that contains mostly plagioclase feldspar and about 30 percent dark silicate

minerals?
Physics
2 answers:
mojhsa [17]2 years ago
5 0

The type of composition that igneous rocks have that contains mostly plagioclase feldspar and about 30 percent dark silicate minerals would be andesitic. I am hoping that this answer has satisfied your query about and it will be able to help you.

dybincka [34]2 years ago
4 0

An igneous rock that contains mostly plagioclase feldspar and about 30 percent dark silicate minerals has a composition that is andesitic. :)


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How do force affect the acceleration of a body?<br><br>​
Arada [10]

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

3 0
2 years ago
A 3200-lb car is moving at 64 ft/s down a 30-degree grade when it runs out of fuel. Find its velocity after that if friction exe
Karolina [17]

Answer:

The velocity is 40 ft/sec.

Explanation:

Given that,

Force = 3200 lb

Angle = 30°

Speed = 64 ft/s

The resistive force with magnitude proportional to the square of the speed,

F_{r}=kv^2

Where, k = 1 lb s²/ft²

We need to calculate the velocity

Using balance equation

F\sin\theta-F_{r}=m\dfrac{d^2v}{dt^2}

Put the value into the formula

3200\sin 30-kv^2=m\dfrac{d^2v}{dt^2}

Put the value of k

3200\times\dfrac{1}{2}-v^2=m\dfrac{d^2v}{dt^2}

1600-v^2=m\dfrac{d^2v}{dt^2}

At terminal velocity \dfrac{d^2v}{dt^2}=0

So, 1600-v^2=0

v=\sqrt{1600}

v=40\ ft/sec

Hence, The velocity is 40 ft/sec.

4 0
3 years ago
Why are slow twitch muscles more beneficiall than fast twitch mucles for cardiorespiratory fitness
Dmitriy789 [7]

Answer:

otherwise known as option D

Explanation:

:)

4 0
3 years ago
Read 2 more answers
How far does a car travel as it accelerates from 12 m/s to 18 m/s at 3 m/s??
yulyashka [42]

Answer:

Explanation:

I ASSUME you mean acceleration is 3 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (18² - 12²) / (2(3))

s = 30 m

to verify we can see that the acceleration time is

t = (18 - 12) / 3 = 2 s

s = 0 + 12(2) + ½(3)2² = 30 m

4 0
2 years ago
At the presentation ceremony, a championship bowler is presented a 1.60-kg trophy which he holds at arm's length, a distance of
nikdorinn [45]

Answer:

a)10.28 Nm

b)9.93 Nm

Explanation:

Let g = 9.81m/s2. First we can calculate the weight of the trophy

W = mg = 1.6 * 9.81 = 15.696 N

(a) The torque is product of force and its moment arm

T = WL = 15.696 * 0.655 = 10.28 Nm

(b) Suppose his arm makes an angle of 15 degree with respect to the horizontal line. We can still calculate the arm length, or the horizontal distance from the trophy to the champion:

L_2 = Lcos(15^0) = 0.655cos(15^0) = 0.655*0.966 = 0.633 m

Again, torque is product of force and its moment arm

T_2 = WL_2 = 15.696 * 0.633 = 9.93 Nm

8 0
3 years ago
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