Find the density of an object that has a mass of 5 kg and a volume of 50 cm3

Physics

2 answers:

Shalnov [3]3 years ago

8 0

Density=mass/volume
=5/50/100*100*100
=100000 kg/m^3
=10^5 kg/m^3

serg [7]3 years ago

3 0

Density = mass/volume. 5000/50= 100 grams per cubic centimeter. No substance on Earth has anywhere near that density. Tops is about 20 for osmium and gold.

You might be interested in

An aircraft acceleration from 100m/s to 300m/s in 100 s what is acceleration

Crank

Answer:

$(300 - 100) \div 100$

8 0

3 years ago

An observer notes that the pitch of a sound is becoming progressively higher.the observer can conclude that the sound is moving

Dahasolnce [82]

The observer can conclude that the sound is moving away from them and that its speed is increasing.

6 0

3 years ago

Which one of the following is not a fundamental physical quantity??! A. Temperature b. Current c. Area d. Mass

Hatshy [7]

Answer:

Out of this, Area is not a fundamental physical quantity.

3 0

2 years ago

Calculate the energy, wavelength, and frequency of the emitted photon when an electron moves from an energy level of -3.40 eV to

jasenka [17]

Answer:

(a) The energy of the photon is 1.632 x $10^{-8}$ J.

(b) The wavelength of the photon is 1.2 x $10^{-17}$ m.

Explanation:

Let;

$E_{1}$ = -13.60 ev

$E_{2}$ = -3.40 ev

(a) Energy of the emitted photon can be determined as;

$E_{2}$ - $E_{1}$ = -3.40 - (-13.60)

= -3.40 + 13.60

= 10.20 eV

= 10.20(1.6 x $10^{-9}$ )

$E_{2}$ - $E_{1}$ = 1.632 x $10^{-8}$ Joules

The energy of the emitted photon is 10.20 eV (or 1.632 x $10^{-8}$ Joules).

(b) The wavelength, λ, can be determined as;

E = (hc)/ λ

where: E is the energy of the photon, h is the Planck's constant (6.6 x $10^{-34}$ Js), c is the speed of light (3 x $10^{8}$ m/s) and λ is the wavelength.