2 years ago

What’s the difference between the speed and velocity of an object?

Physics

1 answer:

Rufina [12.5K]2 years ago

8 0

Answer:

Explanation:

speed if how far an object goes whereas the velocity is the speed in hour or a minute

You might be interested in

Non-native species that have rapidly increasing populations that spread

hjlf

Answer:

Invasive Species

Explanation:

Plz give brainliest

6 0

3 years ago

A temperature of 200°F is equivalent to approximately A. 840°C. B. 93.3°C. C. 232°C. D. 37.8°C

Eduardwww [97]

The equivalent of 200F is 93.3C

5 0

2 years ago

Read 2 more answers

30 POINTS! (Question is located in picture under graph)

harkovskaia [24]

Hi i think its E because the the numbers on both sides are to spread out and are not even one side is 4 and the other is 3

8 0

3 years ago

Read 2 more answers

When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal

Temka [501]

Ans the answer is 0.25J

Explanation

i guess

4 0

3 years ago

Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point

RideAnS [48]

Answer:

a) 2.33 m/s

b) 5.21 m/s

c) 882 m³

Explanation:

Using the concept of continuity equation

for flow through pipes

$A_{1}\times V_{1} = A_{2}\times V_{2}$

Where,

A = Area of cross-section

V = Velocity of fluid at the particular cross-section

given:

$A_{1} = 0.070 m^{2}$

$V_{1} = 3.50 m/s$

a) $A_{2} = 0.105 m^{2}$

substituting the values in the continuity equation, we get

$0.070\times 3.50 = 0.105\times V_{2}$

$V_{2} = \frac{0.070\times 3.5}{0.150}m/s$

$V_{2} = 2.33m/s$

b) $A_{2} = 0.047 m^{2}$

substituting the values in the continuity equation, we get

$0.070\times 3.50 = 0.047\times V_{2}$

$V_{2} = \frac{0.070\times 3.5}{0.047}m/s$

$V_{2} = 5.21m/s$

c) we have,

Discharge $Q = Area (A)\times Velocity(V)$

thus from the given value, we get

$Q = 0.070m^{2}\times 3.5m/s\$

$Q = 0.245 m^{3}/s$

Also,

Discharge $Q = \frac{volume}{time}$

given time = 1 hour = 1 ×3600 seconds

substituting the value of discharge and time in the above equation, we get

$0.245m^{3}/s = \frac{volume}{3600s}$

$0.245m^{3}/s\times 3600 = Volume$

volume of flow = $882 m^{3}$

8 0

3 years ago