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AnnyKZ [126]
3 years ago
8

CHALLENGE

Physics
2 answers:
luda_lava [24]3 years ago
5 0

When the tractor pulls, the boy moves. When the elephant moves, the boy moves. If the elephant moves and has more power than the tractor, the tractor and the boy moves. If the tractor moves and has more power than the elephant, then the elephant and the boy moves. I hope this helps you, have a great day!

Ksivusya [100]3 years ago
4 0
Nxhxjsjdjzjznxjkkdkd
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A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

5 0
3 years ago
A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field
Sophie [7]

Explanation:

direction of electric field is same as that of force experienced by the test charge

8 0
3 years ago
Of all the planets in our solar system, Jupiter has the greatest gravitational strength. If a 1.5 kg pair of running shoes would
Andre45 [30]

Answer:

gₓ = 23.1 m/s²

Explanation:

The weight of an object is on the surface of earth is given by the following formula:

W = mg

where,

W = Weight of the object on surface of earth

m = mass of object

g = acceleration due to gravity on the surface of earth = strength of gravity on the surface of earth

Similarly, the weight of the object on Jupiter will be given as:

W_{x} = mg_{x}

where,

Wₓ = Weight of the object on surface of Jupiter = 34.665 N

m = mass of object = 1.5 kg

gₓ = acceleration due to gravity on the surface of Jupiter = strength of gravity on the surface of Jupiter = ?

Therefore,

34.65 N = (1.5 kg)g_{x}

g_{x} = \frac{34.65 N}{1.5 kg}

<u>gₓ = 23.1 m/s²</u>

7 0
3 years ago
Alguien me ayuda con calculos estequiometricos?
ruslelena [56]

Answer:

SURE!!!...

But what to calculate!!!....

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3 years ago
(physical science) could someone please help me out with this lab? if i’m being honest i did the lab but i lost all of my work :
djverab [1.8K]

Explanation:

hdhhrhhrhehhshsujwuuwuwuwwh

6 0
3 years ago
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