Using the Normal distribution, it is found that 0.0359 = 3.59% of US women have a height greater than 69.5 inches.
In a <em>normal distribution</em> with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
US women’s heights are normally distributed with mean 65 inches and standard deviation 2.5 inches, hence 
.
The proportion of US women that have a height greater than 69.5 inches is <u>1 subtracted by the p-value of Z when X = 69.5</u>, hence:
has a p-value of 0.9641.
1 - 0.9641 = 0.0359
0.0359 = 3.59% of US women have a height greater than 69.5 inches.
You can learn more about the Normal distribution at brainly.com/question/24663213
See the attachment for answers and solving.
Answer:
42 degrees
Step-by-step explanation:
Complimentary angles are two angles whose total is equal to 90 degrees. Since we already know that Angle N measures at 48 degrees, all we have to do is subtract that from 90 degrees to find the measure of Angle I.
90 - 48 = 42
So, the measure of Angle I is 42 degrees! It's pretty easy finding complementary angles once you know how to. I hope this helps! Have a lovely day!! :)
(p.s. I do teaching textbooks too)
This ratio means that there are two men for every three women. So, the ratio of women to men is 3:2.
The total amount of students includes both men and women, so you would use 5. The ratio of women to total student is 3:5.
To find the percent, you divide the first number by the second number and multiply by 100. Our first number is the men, which is 2, and the total students are the second number, or 5.
2/5 = .4 * 100 = 40%
A ratio is the same thing as a fraction, so you take the amount of women (3) and put that over the total student body (5). 3/5 is your fraction.
Good luck, and I hope I helped!
