Lemonade powder is stirred into water until it dissolves. Which are true statements?

Which is the correct symbol for an isotope of helium with 2 neutrons?

SIZIF [17.4K]

The correct symbol is 4He. You may also encounter it displayed as helium-4, He-4.

5 0

3 years ago

One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along

strojnjashka [21]

Answer:

y = -0.42 m

1.16*10^-4 T(-k)

-1.73*10^4 N/C (j)

Explanation:

(a) Above the pair of wires, The field out of the page of the 50 A current will be stronger than the (—k) field of the 30 A current (k).

Between the wires, both produce fields into the page.

below the wires, y = - | y |

B = u_o*I/2πr (-k) + u_o*I/2πr (k)

0 = u_o/2πr[50/ | y |+0.28 (-k) + 30/| y | (k) ]

50 | y | = 30(| y | + 0.28)

| y | = -y

-50 y = 30*(0.28 - y)

y = -0.42 m

b) B = u_o*I/2πr (-k) + u_o*I/2πr (k)

B = 4π*10^-7/2π[ 50/0.28 -1 (-k) +30/1(-k) ]

= 1.16*10^-4 T(-k)

F = qv*B

F = (-2*10^-6)*(150*10^6(i) )(1.16*10^-4(-k))

F = 3.47*10^-2 N(-j)

c) F_e = qE

E = F_e/q

E = 3.47*10^-2/-2*10-6

= -1.73*10^4 N/C (j)

7 0

4 years ago

the thermometer has its stem marked in millimeter instead of degree Celsius. the lower fixed point is 30mm and the upper fixed p

Lorico [155]

10°c

Explanation:

Given parameter;

Lower fixed point = 30mm

Upper fixed point = 180mm

Reading = 45mm

Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

mm-scale °c scale

180mm 100°c

45mm x

30mm 0°c

Solving;

$\frac{x - 0}{100 -0} = \frac{45 - 30 }{180- 30}$

x (150) = 100 x 15

x = 10°c

learn more:

Temperature scales brainly.com/question/1603430

#learnwithBrainly

7 0

4 years ago

The half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su

neonofarm [45]

Answer:

(a) $N=19\times e^{-\lambda t}$

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

$\lambda =\frac {0.6931}{T}$

The equation of radioactivity used here is given by

$N=N_{o}e^{-\lambda t}$

$N=19\times e^{-\lambda t}$

(b) N = 8 gram

Substitute the values in above equation

$\lambda =\frac {0.6931}{12}$

λ = 0.0577 per hour

So, $8=19\times e^{-0.577t}$

$e^{-0.0577t}=0.421$

Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

4 0

3 years ago

Two cars are traveling at the same constant speed v. Car A is moving along a straight section of the road, while B is rounding a

Kamila [148]

Answer:

Car A is not accelerating, but car B is accelerating

Explanation:

Car A is not accelerating because , it is moving with uniform speed in a particular direction . Therefore its velocity too is not changing .

But car B is accelerating because , though its speed is uniform but its velocity is changing due to change in direction . On a circular path , direction of speed changes every moment . Therefore it has an acceleration called centripetal acceleration . Hence car B has acceleration.

7 0

3 years ago