Answer:
Explanation:
We are given that
Initial velocity, u=5.20m/s
We have to find the horizontal component of the initial velocity.
We know that
Horizontal component of velocity=
Using the formula
Horizontal component of the initial velocity=
Horizontal component of the initial velocity=
Horizontal component of the initial velocity=
Hence, the horizontal component of the initial velocity=
Answer:
The velocity of skaters after collision is 0.55 m/s and they are moving to the left
Explanation:
Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.
Consider the velocity along right direction as positive while negative for left direction.
According to the problem,
Mass of first skater, m₁ = 66.0 kg
Mass of second skater, m₂ = 75.0 kg
Velocity of first skater, v₁ = + 2.00 m/s
Velocity of second skater, v₂ = -2.80 m/s
Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.
Applying conservation of linear momentum,
Momentum before collision = Momentum after collision
m₁v₁ + m₂v₂ = (m₁+m₂)v
Substitute the suitable values in the above equation.
66 x 2 - 75 x 2.8 = (66 + 75 )v
v = -0.55 m/s
The negative sign denotes that both the skaters are moving in the left direction.
Answer:
KE = m
Explanation:
In the generation of energy from hydroelectric power station, the motion of water, and the turbines are paramount. The falling flowing water turns the blades of the turbine, which in-turn causes the movement of a coil within a strong magnetic field.
The motion of the coil which cuts the strong magnetic field induces current. Thus, the system generates electrical energy.
The equation that links kinetic energy (KE), mass (m) and speed (v) can be expressed as:
KE = m