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konstantin123 [22]

3 years ago

10

An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15 s? PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE

HELP ME. I’m scared

2 answers:

olasank [31]3 years ago

7 0

Answer:

Power=?,time=15,mass=3,height=50,g=10.

Power=mgh/t......3×10×50=1500/15=100Watts

White raven [17]3 years ago

4 0

Answer:

$\huge \boxed{\mathrm{100 \ Watts}}$

Explanation:

$\sf \displaystyle P=\frac{mgh }{t} \\\\\\ P=power \ (W) \\\\ m=mass \ (kg) \\\\ g=gravity \ acceleration \ (m/s^2) \\\\ h=height \ (m) \\\\ t=time \ taken \ (s)$

$\sf \displaystyle P=\frac{3 \times 10 \times 50 }{15}$

$\sf \displaystyle P=\frac{1500 }{15}$

$\sf \displaystyle P=100$

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Answer:

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Solution:

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Velocity of the tennis ball, v = 120 mph = 54 m/s

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Thickness of the tennis ball, t = 2.0 mm = $2.0\times 10^{- 3}\ m$

Max velocity of the tennis ball, $v_{m} = 200\ mph$ = 89 m/s

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The maximum kinetic energy of the tennis ball is given by:

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Now, the distance the ball can penetrate to is given by:

$\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}$

$\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js$

Thus

$\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}$

$\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}$

$\eta = 1.52\times 10^{-35}\ m$

Now,

We can calculate the tunneling probability as:

$P(t) = e^{\frac{- 2t}{\eta}}$

$P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}$

$P(t) = e^{-2.63\times 10^{32}}$

Taking log on both the sides:

$logP(t) = -2.63\times 10^{32} loge$

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