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stepladder [879]
2 years ago
5

Which quantity is a scalar quantity?

Physics
1 answer:
Vsevolod [243]2 years ago
5 0
The answer is Area ,area
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A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.
Vaselesa [24]
V2=u2+2as
v2=144+600
v2=744
v=√744
6 0
3 years ago
The vapor pressure of ethanol at 293 K is 5.95 kPa and at 336.5 K it is 53.3 kPa. Calculate the enthalpy of vaporization of etha
denis-greek [22]

Answer:

H=41.3kJmol^{-1}

Explanation:

The equation relating the the enthalphy, pressure and temperature is expressed as

ln(\frac{P_{2}}{P_{1}} )=\frac{H}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}} ) \\

Where P is the pressure, H is the enthalphy, and T is the temperature.

since the given values are

T_{1}=293k, \\T_{2}=336.5k\\P_{1}=5.95kPA\\p_{2}=53.3kPA\\and R=8.314J.K^{-1}mol_{-1}

if we insert values, we arrive at

ln(\frac{53.3}{5.95} )=\frac{H}{8.314}(\frac{1}{293}-\frac{1}{336.5} )\\2.19=\frac{H}{8.314}(0.00044)\\H=(2.19*8.314)/0.00044\\H=41,268.8Jmol^{-1}\\H=41.3kJmol^{-1}

4 0
2 years ago
PLEASE HELP
Gennadij [26K]

Answer:

3.675 m

Explanation:

a_{x} =0 v_{xo}=100 a_{y} =-g  v_{yo}=0

X-direction     | Y-direction

R=x_{o}+ v_{xo} t  | y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2

75=100t         |y=0+0+\frac{1}{2} (9.8)(0.75)

\frac{75}{100} =t             | y=3.675 m

0.75s=t              

Hope it helps

3 0
3 years ago
25.5 m/s in 5.75 s. What is the acceleration?
anzhelika [568]
Acceleration units are in m/s^2 , so you take 25.5 m/s divided by 5.75s. Acceleration is the rate of change of velocity :)

follow me on instagram : imrajsingh :):) thanks
7 0
2 years ago
An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti
shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

I=F\Delta t

where:

I is the impulse

F is the force exerted on the object

\Delta t is the time during which the force is applied

For the object in this problem, we have

F=106 N (force applied)

\Delta t= 15.6 s (time interval)

Therefore, the impulse experienced by the object is:

I=(106)(15.6)=1654 kg m/s

3 0
3 years ago
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