Why do scientists need a standard system of measurement?
1 answer:
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Answer: 88 Earth days
Explanation:
According to the Kepler Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>
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In other words, this law states a relation between the orbital period of a body (moon, planet, satellite) orbiting a greater body in space with the size
of its orbit:
(1)
If we assume the orbit is circular and apply Newton's law of motion and the Universal Law of Gravity we have:
(2)
Where is the mass of the massive object and
is the universal gravitation constant. If we assume
constant and larger enough to consider
really small, we can write a general form of this law:
(3)
Where is in units of Earth years,
is in AU (<u>1 Astronomical Unit is the average distane between the Earth and the Sun)</u> and
is the mass of the central object in units of the mass of the Sun.
This means when we are making calculations with planets in our solar system .
Hnece, in the case of Mercury:
(4)
Isolating :
(5)
(6)
This means the period of Mercury is 88 days.
Answer:
W = 2.3 10²
Explanation:
The force of the weight is
W = m g
let's use the concept of density
ρ= m / v
the volume of a sphere is
V = π r³
V = π (1.0 10⁻³)³
V = 4.1887 10⁻⁹ m³
the density of water ρ = 1000 kg / m³
m = ρ V
m = 1000 4.1887 10⁻⁹
m = 4.1887 10⁻⁶ kg
therefore the out of gravity is
W = 4.1887 10⁻⁶ 9.8
W = 41.05 10⁻⁶ N
now let's look for the electric force
F_e = q E
F_e = 12 10⁻¹² 15000
F_e = 1.8 10⁻⁷ N
the relationship between these two quantities is
= 41.05 10⁻⁶ / 1.8 10⁻⁷
\frac{W}{F_e} = 2,281 10²
W = 2.3 10²
therefore the weight of the drop is much greater than the electric force