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Ludmilka [50]
3 years ago
7

How many grams are in 2.54 x 10^23 molecules of CO2

Chemistry
1 answer:
Ivan3 years ago
8 0

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

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What type of bond (Ionic, Covalent or metallic) would be created when titanium bonds with chlorine?
Viktor [21]

Answer:

Covalent

Explanation:

Titanium on reaction with chlorine forms Titanium tetra chloride(TiCl4).

Titanium holds strong covalent bond with chlorine in TiCL4

6 0
2 years ago
Calculate the mole fraction of the ionic species kcl in the solution.
sp2606 [1]

The question is incomplete, here is the complete question:

Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.

<u>Answer:</u> The mole fraction of KCl in the solution is 0.044

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol

  • <u>For KCl:</u>

Given mass of KCl = 43 g

Molar mass of KCl = 74.55 g/mol

Putting values in equation 1, we get:

\text{Moles of KCl}=\frac{43g}{74.55g/mol}=0.577mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For KCl:</u>

Moles of KCl = 0.577 moles

Total moles = [0.577 + 12.5] = 13.077 moles

Putting values in above equation, we get:

\chi_{(KCl)}=\frac{0.577}{13.077}=0.044

Hence, the mole fraction of KCl in the solution is 0.044

8 0
3 years ago
The Molar Mass (g/mol) of an ideal gas whose density is 2.5g/L at 1.8 atm and 30,0 Celsius ?
tia_tia [17]

Answer:

M = 35 g/mol

Explanation:

Given data:

Density = 2.5 g/L

Pressure = 1.8 atm

Temperature = 30°C (273.15 +30 = 303.15 K)

Molar mass = ?

Solution:

d = PM/RT

M = dRT/P

M =  2.5 g/L × 0.0821 atm.L/mol.K ×  303.15 K / 1.8 atm

M = 62.22 atm. g/mol/ 1.8 atm

M = 35 g/mol

8 0
2 years ago
When driving a truck , is fuel crucial why or why not ?
myrzilka [38]
Yes because you have to use fuel to drive that's my guess
3 0
3 years ago
Read 2 more answers
How could you use these solutions to determine the identities of each metal powder?
Anastaziya [24]

Answer:

1.) The nitric acid solution will oxidize and thus dissolve _*(Zn and Pb)*_. This will allow to identify _**Pt**_.

2) To distinguish between _*(Zn and Pb)*_, we can use the nickel nitrate.

3) The nickel nitrate solution will oxidize and thus dissolve _**Zn**_ and will not oxidize or dissolve _**Pb**_.

Explanation:

1) Unlike Zinc and Lead, Platinum does not react with Nitric acid. So, it will be the only metal from step 1 that doesn't react. Pt is identified in this manner.

2) Nickel is higher than Lead in the activity series, but Zinc is higher than both of them in the activity series. This selectivity can be used to distinguish between Zinc and Lead metal powders.

3) Because Zinc is higher than Nickel in the activity series, it means that Zinc metal can and will displace Nickel from Nickel Nitrate solution. Therefore the Nickel Nitrate solution will oxidize and dissolve the Zinc metal.

But, there will be no reaction with the Lead metal powders sample as Pb is lower than Ni in the activity series, so, Nickel Nitrate solution will not oxidize or dissolve the Lead metal powders.

5 0
3 years ago
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