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3 years ago

How many grams are in 2.54 x 10^23 molecules of CO2

Chemistry

1 answer:

Ivan3 years ago

8 0

Answer:

= 0.42 moles of CO2

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

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What would be the products for the reaction Br2 + KI →? (Just identify the correct products for the reaction. You do not need to

Savatey [412]

Answer: The products of the reaction will be $I_2\text{ and }KBr$

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The general chemical equation for the single displacement reaction follows:

$A+BC\rightarrow AC+B$

The given chemical equation follows:

$Br_2+2KI\rightarrow I_2+2KBr$

Bromine element is more reactive than iodine element. Thus, can easily replace iodine from its chemical reaction.

Hence, the products of the reaction will be $I_2\text{ and }KBr$

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4 years ago

Determine if each statement is True or False. [ Select ] Central atoms with four electron groups will be sp3 hybridized. [ Selec

meriva

Answer:

Central atoms with four electron groups will be sp3 hybridized. True

Hybrid orbitals are delocalized over the entire molecule. False

The number of hybrid orbitals is equal to the number of atomic orbitals that are blended together. True

Atoms with a single pi bond and an octet are sp2 hybridized. True

Sometimes oxygen atoms will be sp3d hybridized in organic molecules. False

All resonance structures must be considered when assigning hybridization. False

Explanation:

When a central atom has four electron groups attached to it, then it must be sp3 hybridized. This is the case in ammonia, water, hydrogen sulphide, methane etc.

Hybridization is a valence bond concept while delocalization is a molecular orbital theory concept. Hybridized orbitals are localized on central atoms in a molecule while delocalized orbitals spread across the entire molecule.

According to valence bond theory, the number of atomic orbitals that combined to give hybrid orbitals must be equal to the number of hybrid orbitals formed.

When an atom has a single pi bond and on octet of electrons, then it must be sp2 hybridized. Remember that in ethene for instance, carbon has one pi bond and an octet of electrons.

Oxygen has an empty n=3 level hence it can not have d-orbitals involved in hybridization.

The electron domain geometry of the molecule is considered when assigning hybridization and not the resonance structures. All the resonance structures must have the central atom in the same hybridization state.

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3 years ago

The graph shows the volume of a gaseous product formed during two trials of a reaction. A different concentration of reactant wa

solniwko [45]

A: Trial 1, because the average rate of the reaction is lower.

The rate of reaction is the speed with which reactants are converted into products. It is also the rate at which reactants disappear and products appear. The higher the rate of reaction, the greater the amount of product formed in a reaction.

If we look at the graph, we will realize that trial 1 produces a lesser amount of product than trial 2. This implies that the average rate of the reaction in trial 1 is lower than in trial 2.

Lower average rate of reaction implies lower concentration of the reactants since the rate of reaction depends on the concentration of reactants.

Hence trial 1 has a lower concentration of reactants because the average rate of the reaction is lower.

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3 years ago

Read 2 more answers

Is density physical or chemical

stepan [7]

Density is a physical

6 0

3 years ago

For the following reaction, the equilibrium constant Kc is 2.0 at a certain temperature. The reaction is endothermic. What do yo

jeyben [28]

Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

$2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)$

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

7 0

3 years ago