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Ludmilka [50]
3 years ago
7

How many grams are in 2.54 x 10^23 molecules of CO2

Chemistry
1 answer:
Ivan3 years ago
8 0

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

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Which moon phase does a solar eclipse occur in?
VARVARA [1.3K]

Answer:

full moon, i think

Explanation:

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3 years ago
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Below is the equation of sucrose and sulfuric acid-producing carbon, water vapor and sulfur dioxide.
Karolina [17]

Answer:

11 is the coefficient for C to balance the equation

Explanation:

C₁₂H₂₂O₁₁(s)  +  H₂SO₄(aq)  +  1/2 O₂(g)   → 11C(s) + CO₂(g) + 12H₂O(g) + SO₂(g)

12 Carbons in left side   →   12 Carbons in right side

12 in sucrose → 11 in solid C + 1 in the CO₂

24 Hydrogens in left side → 24 Hydrogens in right side

22 in sucrose + 2 in sulfuric → 24 in water vapor

1 S in left side → 1 S in right side

1 S in sulfuric → 1 S in sulfur dioxide

16 O in left side → 16 O in right side

11 O in sucrose + 4 in sulfuric + 1 O at ground state → 2 O in carbon dioxide + 12 in water vapor + 2 in sulfur dioxide

7 0
3 years ago
How many sulfur atoms does 2Ba (S03)3 have
grandymaker [24]

Answer:

it has 9 sulfur atoms

Explanation:

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6 0
3 years ago
What holds everything in place in the universe?
tresset_1 [31]

Answer:

Gravity

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Explanation:

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3 years ago
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Calculate the number of mg of Mn2+ left
soldi70 [24.7K]

Answer:

1.930 * 10⁻⁹ mg of Mn⁺² are left unprecipitated.

Explanation:

The reaction that takes place is:

Mn⁺² + S⁻² ⇄ MnS(s)  

ksp = [Mn⁺²] [S⁻²]

If the pksp of MnS is 13.500, then the ksp is:

ksp=10^{-13.500}=3.1623*10^{-14}

From the problem we know that [S⁻²] = 0.0900 M

We use the ksp to calculate [Mn⁺²]:

3.1623*10⁻¹⁴= [Mn⁺²] * 0.0900 M

[Mn⁺²] = 3.514 * 10⁻¹³ M.

Now we can calculate the mass of Mn⁺², using the volume, concentration and atomic weight. Thus the mass of Mn⁺² left unprecipitated is:

3.514 * 10⁻¹³ M * 0.1 L * 54.94 g/mol = 1.930 * 10⁻¹² g = 1.930 * 10⁻⁹ mg.

6 0
3 years ago
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