1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ludmilka [50]
3 years ago
7

How many grams are in 2.54 x 10^23 molecules of CO2

Chemistry
1 answer:
Ivan3 years ago
8 0

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

You might be interested in
When copper oxide is reacted with sulfuric acid, the acid is often gently heated. This is done in order to:
pav-90 [236]
Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)

In equation form:

CuO +H2SO4 -> CuSO4 + H2O

The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.

If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.
7 0
3 years ago
How many grams of O are in 675 g of Na2O
PIT_PIT [208]
I think it is .00005815
6 0
3 years ago
Which place in the world has the highest average annual precipitation?
alekssr [168]

Answer: Colombia

Explanation:

6 0
3 years ago
Read 2 more answers
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
Which of the following contribute(s) to most of the mass of an atom?
xenn [34]

Answer:

1.

B) protons and newtrons

2.

D)

3.

C)

4.

A)

6 0
3 years ago
Other questions:
  • So2−3(aq)→so2−4(aq) (basic solution) express your answer as a chemical equation. identify all of the phases in your answer. so32
    6·1 answer
  • you go out to dinner and the bill comes to $35.51. how much should you tip if you want the tip to be 20% of the bill.​
    14·2 answers
  • A student performs a titration procedure by adding NaOH to a solution that contains H+ ions. She added the indicator, phenolphth
    10·1 answer
  • When dissolved in water, an acid yield ??
    9·1 answer
  • Why do non-metal aroms form covalent bonds e.g. H2O​
    5·1 answer
  • The reproductive organs of the male
    11·2 answers
  • How many g of N in 2.76 g Al(NO3)3
    8·1 answer
  • In this activity, you will plan and conduct an investigation to compare a single property
    14·1 answer
  • Solve 21 and 22 please
    9·1 answer
  • Complete the sentence using ide, ate or Ic. To determine the name of an anion, you take the name of its element and replace the
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!