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nikitadnepr [17]
3 years ago
14

If sin theta = 1/2 and pi/2 < theta < pi , what are the values of cos and tan?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

  • cos(θ) = -(√3)/2
  • tan(θ) = -(√3)/3

Step-by-step explanation:

Referring to the attached short table of trig functions, we see that the reference angle with sin(θ) = 1/2 is π/6. The table also shows cosine and tangent values for that angle.

In the second quadrant, where π/2 < θ < π, the cosine and tangent are both negative. The values you seek are ...

  cos(θ) = -(√3)/2

  tan(θ) = -1/√3 = -(√3)/3

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If sin θ = cot θ, then, what is the value of cos θ + 2 cos^2 θ + 2 cos^3 θ + cos^ 4 θ ?
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Notice that

cos(θ) + 2 cos²(θ) + 2 cos³(θ) + cos⁴(θ)

= cos(θ) (1 + 2 cos(θ) + 2 cos²(θ) + cos³(θ))

= cos(θ) ([1 + cos(θ)] + [cos(θ) + cos²(θ)] + [cos²(θ) + cos³(θ)])

= cos(θ) ([1 + cos(θ)] + [cos(θ) (1 + cos(θ))] + [cos²(θ) (1 + cos(θ))])

= cos(θ) (1 + cos(θ)) (1 + cos(θ) + cos²(θ))

Given that sin(θ) = cot(θ), by definition of cotangent this tells us that

sin(θ) = cos(θ)/sin(θ)   ⇒   cos(θ) = sin²(θ)

and by the Pythagorean identity

cos²(θ) + sin²(θ) = 1

it follows that

cos(θ) = sin²(θ) = 1 - cos²(θ)

Substituting these results into the factorization above gives

cos(θ) (1 + cos(θ)) (1 + cos(θ) + cos²(θ))

= cos(θ) (1 + cos(θ)) (1 + [1 - cos²(θ)] + cos²(θ))

= 2 cos(θ) (1 + cos(θ))

= 2 sin²(θ) (1 + cos(θ))

= 2 (1 - cos²(θ)) (1 + cos(θ))

= 2 (1 + cos(θ) - cos²(θ) - cos³(θ))

= 2 (cos(θ) + cos(θ) - cos³(θ))

= 2 (2 cos(θ) - cos³(θ))

= 2 cos(θ) (2 - cos²(θ))

= 2 cos(θ) (1 + cos(θ))

= 2 (cos(θ) + cos²(θ))

= 2 (1 - cos²(θ) + cos²(θ))

= 2

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3 years ago
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Igoryamba

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Step-by-step explanation:

Three friends went out to eat dinner the bill came to 35.60. This means that the total bill for the dinner was 35.60.

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Step-by-step explanation:

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