Answer:
<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>
Explanation:
<u>Mechanical Force</u>
The second Newton's law states the net force exerted by an external agent on an object of mass m is:
Where is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.
This means the net force and the acceleration have the same direction.
The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:
As stated above its direction is the same as the acceleration, thus:
The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.
Answer:
It gives you the symbol, mass, and the number of protons, neutrons, and electrons of elements.
Answer:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
Explanation:
In this case, we see a disk rotating at constant rate, the travelled distance of a point on the outside rim (), in centimeters, is determined by using this expression:
(1)
Where:
- Angular speed, in radians per second.
- Radius of the disk, in centimeters.
- Time, in seconds.
If we know that , and , then the travelled distance of the point is:
The point will travel a distance of 15708 centimeters in 30 seconds of rotation.
B.sunnny cold probable rain
Let's call
the frequency of the nth-harmonic and
the frequency of the (n+1)th harmonic, wish is the next harmonic.
Since the frequency of the nth-harmonic is n times the fundamental frequency f1:
then the difference between two successive harmonics is equal to the fundamental frequency of the tube:
so, by using 350 Hz and 280 Hz as successive harmonics, we find the fundamental frequency of the tube:
The wavelength of the first harmonic is twice the length of the tube:
And since we know both frequency and wavelength, we can find the speed of the wave in the tube, which is the speed of sound in the gas in the tube: