Answer:
(a) Bus will traveled further a distance of 40 m
(b) It will take 7.5 sec to stop the bus
Explanation:
We have given initial velocity of the bus u = 24 m/sec
And final velocity v = 16 m/sec
Distance traveled in this process s = 50 m
From third equation of motion we know that ![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
![16^2=24^2+2\times a\times 50](https://tex.z-dn.net/?f=16%5E2%3D24%5E2%2B2%5Ctimes%20a%5Ctimes%2050)
![a=-3.2m/sec^2](https://tex.z-dn.net/?f=a%3D-3.2m%2Fsec%5E2)
(a) Now as the bus finally stops so final velocity v = 0 m/sec
So ![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
![0^2=24^2-2\times 3.2\times s](https://tex.z-dn.net/?f=0%5E2%3D24%5E2-2%5Ctimes%203.2%5Ctimes%20s)
s= 90 m
So further distance traveled by bus = 90-50 =40 m
(b) Now as the bus finally stops so final velocity v= 0 m/sec
Initial velocity u = 24 m/sec
Acceleration ![a=-3.2m/sec^2](https://tex.z-dn.net/?f=a%3D-3.2m%2Fsec%5E2)
So time ![t=\frac{v-u}{a}=\frac{0-24}{-3.2}=7.5sec](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bv-u%7D%7Ba%7D%3D%5Cfrac%7B0-24%7D%7B-3.2%7D%3D7.5sec)
To determine the amount in grams of the iron, we need data on the density of iron. From literature, it has a value of <span>p=7.9 g/cm3. We simply multiply the volume to the density. We do as follows:
mass = 3.70 (7.9) = 29.23 g Fe
Hope this answers the question. Have a nice day.</span>