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lora16 [44]
3 years ago
13

The the symptoms and treatments for these common nervous system

Physics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

the symptoms are cough, cold, cattah and the treatment is antibiotics

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What is the equivalent resistance if you connect three 10.0 Ω resistors in series?
Sonja [21]

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

4 0
3 years ago
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Which of these would most likely cause a sound wave?
Levart [38]
Among the choices the one that most likely cause a sound wave is C or the a spoon hitting the side of a bowl while mixing <span>because that's going to make a sound.

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3 years ago
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How do you ask someone out?
vazorg [7]

talk, make conversation. text isnt always the answer, but sadly now it is. text them or better yet, call them. you can talk and then do not just blurt it out. say it calmly. they say yes, congrats, but if they say no, do not have a mental breakdown. it might ruin a friendship.

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3 years ago
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Two planets have the same surface gravity, but planet b has twice the radius of planet
vampirchik [111]
Planet A;
m = the mass 
Let r =  the radius 

Planet B:
Let M =  the mass
The radius is 2r (twice the radius of planet A)

The surface gravitational acceleration of planets A and B (they have the same surface gravity) are
g= \frac{Gm}{r^{2}} \, and \, g= \frac{GM}{(2r)^{2}} \\\\ m= \frac{M}{4} \\\\ M=4m

Answer: The mass of planet B is 4m.
3 0
3 years ago
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A velocity selector, in which charged particles of a specific speed pass through undeflected while those of greater or lesser sp
uranmaximum [27]

Answer:

a) 351351.35m/s

b) 1.044*10^{-8}kg/C

Explanation:

a) Electric force and magnetic force over the charge must have the same magnitude. From there we can compute the seep of the charge.

F_E=F_B\\\\qE=qvB\\\\v=\frac{E}{B}=\frac{1.95*10^{5}V/m}{0.555T}=351351.35\frac{m}{s}

b) the mass-charge ratio is given by:

\frac{m}{q}=\frac{rB}{v}=\frac{(6.61*10^{-3}m)(0.555T)}{351351.35m/s}=1.044*10^{-8}\frac{kg}{C}

hope this helps!!

5 0
3 years ago
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