The the symptoms and treatments for these common nervous system

Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 2.70 m/s. Her husband Bruce suddenly realiz

Katen [24]

Answer:

The velocity is $v = 6.66 \ m/s$

Henrietta is at distance $s= 18.17 \ m$ from the under the window

Explanation:

From the question we are told that

The speed of Henrietta is $v= 2.70 \ m/s$

The height of the window from the ground is $h = 36.5 \ m$

Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is

$t = \sqrt{\frac{2 * h }{g} }$

=> $t = \sqrt{\frac{2 * 36.5 }{9,8} }$

=> $t = 2.73 \ s$

Generally the time taken for the lunch to reach Henrietta is mathematically represented as

$T = t + t_1$

Here $t_1$ is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s

Now

$T = 2.73 + 4$

=> $T = 6.73 \ s$

Generally the distance covered by Henrietta before catching her lunch is

$s= v * T$

=> $s= 2.70 * 6.73$

=> $s= 18.17 \ m$

Generally the speed with which Bruce threw her lunch is mathematically represented as

$v = \frac{18.17}{2.73}$

$v = 6.66 \ m/s$

4 0

3 years ago

As an intern with an engineering firm, you are asked to measure the moment of inertia of a large wheel, for rotation about an ax

AysviL [449]

Answer:

$I=2.766\ kg.m^2$

Explanation:

We have:

diameter of the wheel, $d=0.88\ m$

weight of the wheel, $w_w=280\ N$

mass of hanging object to the wheel, $m_o=6.32\ kg$

speed of the hanging mass after the descend, $v_o=4\ m.s^{-1}$

height of descend, $h=2.5\ m$

(a)

moment of inertia of wheel about its central axis:

$I=\frac{1}{2} m.r^2$

$I=\frac{1}{2} \frac{w_w}{g}.r^2$

$I=\frac{1}{2} \times \frac{280}{9.8}\times 0.44^2$

$I=2.766\ kg.m^2$

3 0

3 years ago

PRACTICE ANOTHER A cube of wood having an edge dimension of 19.7 cm and a density of 647 kg/m3 floats on water. (a) What is the

dedylja [7]

CHECK COMPLETE QUESTION

The cube of wood having an edge dimension of 19.7cm and a density of 647kg/m3 floats on water

(a) What is the distance from the horizontal top surface of the cube to the water level answer in cm

(b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface answer in kg

Answer:

a)6.29cm

b)2.78 kg

Explanation:

Given:

Let us calculate the volume first, we were given dimension as 19.7cm=0.197m

Volume is (0.197 meters)³ = 0.00764m³

Then we can calculate the mass as;

Given mass is 647 kg/m³ x 0.00774m³ = 4.947kg

The weight = mass × acceleration due to gravity

weight = 4.947 x 9.8 N/kg = 48.44N

By Floating we can say the the buoyancy force has to equal the weight (48.44 N) which has

which is equal to the weight of volume of the displaced water. Or the mass, the calculation is the same.

We know that density of fresh water at 20ºC is 998 kg/m³

Then we can calculate the volume of displaced water as

4.947 kg / 998 kg/m³ = 0.00496 m³

We know that the displaced water has a shape of a rectangular solid with 0.197 meters on the two horizontal dimensions, and h as the height to the surface then

V = 0.197²h = 0.00496

0.00496= 0.197²h

h = 0.1278 meters or 12.78 cm

Then the the distance exposed, would be 19.7–12.78 = 6.29 cm

b) ifthe cube is fully submerged, the volume of the displaced water is 0.00774m³

mass of displaced water is 0.00774m³ x 998 kg/m³ = 7.724 kg

Added mass is the mass of the displaced water – mass of block

= 7.724–4.947 = 2.78 kg

5 0

2 years ago

¿Qué significa que la investigación debe ser replicable? Analiza.

Inga [223]

Significa que en su investigación, debe proporcionar suficiente información para que otras personas que lean su investigación puedan hacer la investigación nuevamente.

4 0

3 years ago

Two coils of wire are placed close together. Initially, a current of 3.04 A exists in one of the coils, but there is no current

Alchen [17]

Answer:

$M=0.0247H$

Explanation:

Given data

$V_{voltage}=4.29V\\I_{current}=3.04A\\t_{time}=1.75*10^{-2}s$

To find

Mutual inductance of the two-coil system

Solution

The mutual inductance given as:

M= (-VΔt)/ΔI

Substitute the given values

So

$M=-\frac{4.29V*1.75*10^{-2}s}{(0-3.04A)}\\ M=0.0247H$

4 0

3 years ago