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3 years ago

After the body has begun shivering, what explains why it would stop shivering?

Physics

2 answers:

Alexus [3.1K]3 years ago

4 0

Answer: The internal temperature of the body is maintained by the phenomenon known as homeostasis.

Explanation: Homeostasis is the phenomenon by which the internal temperature of the body is maintained.

Once the body feels cold, it starts shivering to maintain warmth in the body by the movement of skeletal muscles.

This phenomenon of maintaining the body temperature is known as Homeostasis. Once the body temperature is maintained shivering stops.

Oksana_A [137]3 years ago

3 0

The body shivers to produce energy and it uses the energy to keep it warm. The body would stop shivering when it has produced enough energy to keep it warm and the atmosphere around it has got warmer

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Answer:

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3 years ago

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CaHeK987 [17]

Answer:B

Explanation:

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3 years ago

Which statement is correct about the car?

JulijaS [17]

Answer:

Explanation:

OOf we are doing this stuff atm

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3 years ago

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A ball is dropped from rest at a point 12 m above the ground into a smooth, frictionless chute. The ball exits the chute 2 m abo

Nonamiya [84]

Answer:

29,7 m

Explanation:

We need to devide the problem in two parts:

A) Energy

B) MRUV

Energy:

Since no friction between pint (1) and (2), then the energy conservatets:

Energy = constant ----> Ek(cinética) + Ep(potencial) = constant

Ek1 + Ep1 = Ek2 + Ep2

Ek1 = 0 ; because V1 is zero (the ball is "dropped")

Ep1 = m*g*H1

Ep2= m*g*H2

Then:

Ek2 = m*g*(H1-H2)

By definition of cinetic energy:

m*(V2)²/2 = m*g*(H1-H2) ---> $V2 = \sqrt{(2*g*(H1-H2)}$

Replaced values: V2 = 14,0 m/s

MRUV:

The decomposition of the velocity (V2), gives a for the horizontal component:

V2x = V2*cos(α)

Then the traveled distance is:

X = V2*cos(α)*t.... but what time?

The time what takes the ball hit the ground.

Since: Y3 - Y2 = V2*t + (1/2)*(-g)*t²

In the vertical axis:

Y3 = 0 ; Y2 = H2 = 2 m

Reeplacing:

-2 = 14*t + (1/2)*(-9,81)*t²

solving the ecuation, the only positive solution is:

t = 2,99 sec ≈ 3 sec

Then, for the distance:

X = V2*cos(α)*t = (14 m/s)*(cos45°)*(3sec) ≈ 29,7 m

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4 years ago

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