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marishachu [46]
3 years ago
9

When you dissolve covalent compounds in water, the molecules tend to stick together but if you dissolve ionic compounds in water

, the formula units tend to disassociate. What can you infer about which type of bond is stronger?
Chemistry
1 answer:
9966 [12]3 years ago
5 0
A covalent bond is stronger than an ionic bond because the covalent bond doesn’t separate in water
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The reaction between between common salt and concentrated tetraoxosulphate(vi) acid will liberate
Vedmedyk [2.9K]

most prolly option D

Explanation:

NaCl + H2SO4 -> Na2SO4 + HCl[g]

5 0
3 years ago
Read 2 more answers
HELP I NEED HELP ASAPP
Effectus [21]

Answer:

B = A/DH – C

Explanation:

From the question given above, we obtained:

A = D • H(B + C)

Thus, we can obtain B in terms of D, H, A and C by doing the following:

A = D • H(B + C)

A = DH(B + C)

Divide both side by DH

A/DH = B + C

Subtract C from both side

A/DH – C = B + C – C

A/DH – C = B

B = A/DH – C

4 0
2 years ago
Concept Review<br> 14.11. Can a reaction that is not reversible achieve chemical equilibrium?
MakcuM [25]

Answer:

No

Explanation:

Chemical equilibrium is reached by the forward reaction rate equaling the reverse reaction rate. If the reaction is not reversible, this could not occur.

7 0
3 years ago
The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be
dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

6 0
3 years ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
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