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Mrac [35]
3 years ago
14

If the measured gas pressure in a collection flask during a gas-forming reaction was determined to be 1.44 atm? If the measured

gas pressure in a collection flask during a gas-forming reaction was determined to be 1.44 atm, and the atmospheric pressure that day was measured as 0.95 atm, what is the partial pressure of the gas produced by the reaction?
Chemistry
1 answer:
ryzh [129]3 years ago
6 0
With the information given most likely in order to find the partial pressure of the gas produced you have to subtract the total air pressure in the collection flask by the atmospheric pressure since you assume that the flask started with atmospheric pressure when it was sealed and then the gas was added as the reaction took place increasing the pressure.
1.44atm-0.95 atm=0.49atm
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What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm
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Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error



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