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ivanzaharov [21]
3 years ago
8

Convert an acceleration of 1km/h^2 into cm/8^2?

Physics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

1km/h^2 = 5/648 cm/s^2 [about 7.7 x 10^(-3) /s^2]

Explanation:

1km = 10^3 m = 10^5 cm

1h = 60x60 = 3600s

--> 1km/h^2 = 10^5 cm / (3600^2) s^2

<=> 1km/h^2 = 5/648 cm/s^2 [about 7.7 x 10^(-3) /s^2]

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Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
Mrrafil [7]

Answer:

The chance in distance is 25 knots

Explanation:

The distance between the two particles is given by:

s^2 = (x_A - x_B)^2+(y_A - y_B)^2  (1)

Since A is traveling north and B is traveling east we can say that their displacement vector are perpendicular and therefore (1) transformed as:

s^2 = x_B^2+y_A^2 (2)

Taking the differential with respect to time:

\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

where \displaystyle{\frac{dx_B}{dt}}=v_B and \displaystyle{\frac{dx_A}{dt}}=v_A are the respective given velocities of the boats. To find s and x_B we make use of the given position for A, y_A=30, the Pythagoras theorem and the relation between distance and velocity for a movement with constant velocity.

\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

with this time, we know can now calculate the distance at which B is:

\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

and applying Pythagoras:

\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

Now substituting all the values in (3) and solving for  \displaystyle{\frac{ds}{dt} } we get:

\displaystyle{\frac{ds}{dt} = \frac{1}{2s}(2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt})}\\\displaystyle{\frac{ds}{dt} = 25 \ knots}

4 0
3 years ago
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Answer:

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4 0
3 years ago
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ehidna [41]

Explanation:

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brainly.com/question/3373457

brainly.com/question/8612368

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3 years ago
4. What is the acceleration of the car in each section?<br> b<br> с<br> d<br> a
makvit [3.9K]

Answer:

0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s.

Explanation:

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2 years ago
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How to change this to mega and giga prefixes?urgent .thankyou
Akimi4 [234]
3*10^{8} m = 3*10^{5} km = 3*10^{2} Mm = 3*10^{-1} Gm

Each increase in the prefix is a division by 1000.
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