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4 years ago

Convert an acceleration of 1km/h^2 into cm/8^2?

Physics

1 answer:

Oduvanchick [21]4 years ago

5 0

Answer:

1km/h^2 = 5/648 cm/s^2 [about 7.7 x 10^(-3) /s^2]

Explanation:

1km = 10^3 m = 10^5 cm

1h = 60x60 = 3600s

--> 1km/h^2 = 10^5 cm / (3600^2) s^2

<=> 1km/h^2 = 5/648 cm/s^2 [about 7.7 x 10^(-3) /s^2]

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A soccer player kicks the ball with a velocity of 10 m/s at an angle of 80 degreees to the horizontal. Find the horizontal and v

worty [1.4K]

Answer:

Horizontal component of velocity =1.7364m/s

Vertical component of velocity =9.848m/s

Explanation:

As the ball is a 2D projectile,it has two components.

Concept of components of a vector:

1)All the possible independent components of a vector sum up to give the vector.

2)If the magnitude of a vector is v,then its component in the direction at an angle of Θ from the vector is equal to - vcos(Θ).

Now as the ball is having 2D motion,it has two independent components one along the horizontal,one along the vertical.

Given angle of velocity with horizontal $\alpha$ = $80$ °

Therefore angle of velocity with vertical $\beta = 90$ ° $-80$ °

$\beta =10$ °

Therefore,

Component of Velocity along horizontal = $vcos(\alpha )$

$v_{x}=10\times$ cos(80°)

$1.7364m/s$

Component of velocity along vertical = $vsin(\beta )$

$v_{y}=10\times$ cos(10°)

$v_{y}= 9.848m/s$

Therefore

Horizontal component of velocity of ball $v_{x}$ =1.7364m/s

Vertical component of velocity of ball $v_{y}$ =9.848m/s

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3 years ago

A circular loop in the plane of a paper lies in a 0.75 T magnetic field pointing into the paper. The loop's diameter changes fro

Arte-miy333 [17]

Answer:

Explanation:

A.the direction of induced current will be clockwise

B: Changing 18cm and 6.8cm into 0.18m and 0.68

2.5

Divide them both by 2 to find the radius . Now we have 0.09 and .034m.

Now use Φ=(π*0.09^2)(.75 T)cos0 and the 0.019wb

(π*0.034^2)(.75 T)cos0 and the 0.00272wb

ow use ε=-N(ΔΦ/Δt)

For ΔΦ, 0.091-0.0027=0.0883

To find the current, use I=ε/R

0.0883/2.5= 0.035A

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In your own words, explain why Mendeleev believed the data on this new element must have been wrong.

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